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Questions tagged [hardy-spaces]

For questions about Hardy spaces. Use the other related tag like (tag: complex-analysis) or (operator-theory).

-2 votes
0 answers
83 views

Let $f$ be a function of bounded type (Nevanlinna class) in the unit disk $\mathbb{D}$. Suppose: $f$ is analytic and zero-free in $\mathbb{D}$; Both $f$ and $1/f$ are of bounded type in $\mathbb{D}$; ...
davlovsky's user avatar
0 votes
0 answers
48 views

I am reading Stein and Shakarchi's Real Analysis, and have got stuck on an example of how orthogonal projections work. The book states the following: Consider $L^2([-\pi,\pi])$, and let $S$ denote ...
R. Reed's user avatar
  • 355
0 votes
0 answers
40 views

This is from the book Hardy spaces on the Euclidean space by Akihito Uchiyama. In page 14-16, the author give the following lemma: Lemma 1.2. Let $a>0$, $\varphi \in \mathcal{D}$, $\int\varphi(x)dx ...
Bully Gary's user avatar
2 votes
0 answers
139 views

Let $ 1 \leq p \leq +\infty $ and $ g \in \mathcal{H}(\mathbb{D}) $. Consider the multiplication operator $ M_g(f) = g f $. I want to characterize the functions $ g $ for which the operator $ M_g : H^...
Mths's user avatar
  • 53
1 vote
0 answers
34 views

Let $H^{\infty}(\mathbb{D})$ denote the Hardy space of the unit disc consisting of the bounded analytic functions on the open unit disk $\mathbb{D}$. An outer function $f \in H^{\infty}(\mathbb{D})$ ...
liamsi Meean's user avatar
2 votes
0 answers
55 views

The atomic Hardy space $H_1(\mathbb{R})$ is space of functions in $L_1(\mathbb{R})$ of the from $$ f(x) = \sum_{i=0}^\infty \lambda_i a_i $$ where $(\lambda_i)_i$ is in $\ell_1$, and each $a_i$ is an ...
Banach333's user avatar
1 vote
1 answer
63 views

I was solving some exercises on proving Banach Space. A question is given in the following way: Let $D$ denote the open unit disk in $\mathbf{C}$. Let $A:=\{x\in C(\bar{D}):x$ is analytic on $D\}$. ...
Pro_blem_finder's user avatar
2 votes
0 answers
88 views

Can a non-constant inner function map the unit circle on a proper subset of itself? Intuitively, I guess the answer is negative and I suppose there should be a relatively simple argument but I could ...
user163644's user avatar

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