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Questions tagged [puzzle]

For questions about the mathematical principles behind puzzle, games, riddles, or their possible solutions. Questions that are not strictly mathematical in nature should be asked on Puzzling Stack Exchange.

0 votes
1 answer
48 views

We flip a coin $n$ times. The probability of tails is $p$. Let $X$ be the number of occurrences of a run of heads followed by a longer run of tails. We can also agree that if the sequence begins with ...
ploosu2's user avatar
  • 12.6k
1 vote
1 answer
86 views

Two players, $A$ and $B$, play the following game. Player $A$ chooses an integer $x$ between $1$ and $10$. Then, starting with player $B$, the players take turns adding to $x$ any integer between $1$ ...
framago's user avatar
  • 1,954
-1 votes
1 answer
80 views

Let $R_{m,n}$ be an $m$x$n$ rectangle where $m$ is the width and $n$ is the length, and $R_{m,n}$ is subdivided into a grid of unit squares. A line segment is a horizontal or vertical segment drawn ...
ILoveMath79's user avatar
0 votes
1 answer
51 views

For clarification, s sets of all asymmetric n-ominoes means s copies of each of the k asymmetric n-ominoes. Non-trivial means that for $n = 5$, you can’t take the F, L, P, N, Y pentominoes and do this ...
ILoveMath79's user avatar
4 votes
1 answer
75 views

If the wording of the question was a little confusing, here is the main idea: Some $n$-ominoes cannot tile rectangles. We are excluding those. Excluding those $n$-ominoes not tiling any rectangle, ...
ILoveMath79's user avatar
2 votes
0 answers
85 views

Some context and motivation for this question: A friend posed to me the following puzzle. Given eight points in the unit disc, why must there exist a pair of points with distance less than $ 1 $? The ...
Cranium Clamp's user avatar
3 votes
1 answer
43 views

For any $n$, what's the minimum number of sets needed for all free $n$-ominoes to be able to be tiled in a rectangle? For $n = 1$ and $n = 2$ the answer is 1 as there is only one monomino and domino. ...
ILoveMath79's user avatar
9 votes
1 answer
694 views

I just read this riddle which i find quite interesting: Two friends are staying at the same hotel. While chatting in the lobby, one says to the other: "The difference between the least common ...
Michele Ferrari's user avatar
3 votes
0 answers
59 views

Finding solution of a Sliding Puzzle of size $N \times N$. asks about solving a sliding-block puzzle with multiple holes. Apparently a 2-hole puzzle is always solvable; as those who've played with the ...
John Hughes's user avatar
16 votes
3 answers
1k views

I believe context will help before the statement of the problem. I was asked In the picture below, can you find a closed, non-intersecting loop visiting every white square exactly once? (If you do, ...
Maxime Jaccon's user avatar
8 votes
2 answers
261 views

In 1981, Kontsevich proposed the following problem. Imagine a chessboard that extends infinitely in only two directions: upwards and to the right. Put one pebble in each colored cell of the figure (...
hdecristo's user avatar
  • 1,261
3 votes
0 answers
97 views

I am exporting slides to pdf at an Optoma interactive touchscreen display I use in my lectures. The order of pages in the exported pdf is shuffled and I am trying to understand the logic how the ...
Jan Zapal's user avatar
  • 3,709
5 votes
1 answer
207 views

I am looking for some probability problems in which there is a symmetry that you don't notice in the first place, but by noticing it, you can easily get the answer. I have two examples in mind, and in ...
MR_BD's user avatar
  • 6,477
8 votes
3 answers
238 views

Happy September 27th, 2025! A good friend of mine, let's call him Bob, wrote to me today with an interesting tidbit. Write Sept. 27th, 2025 in Month-Day-Year notation to get 09/27/2025. If you remove ...
questionasker's user avatar
1 vote
0 answers
72 views

I am working with a physical puzzle consisting of 32 unique pieces. Each piece can only connect to certain other pieces, and all pieces must be connected together into one single assembly. There are ...
Leo Vickman's user avatar

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