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Questions tagged [riemann-hypothesis]

Questions on the Riemann hypothesis, a conjecture on the behavior of the complex zeros of the Riemann $\zeta$ function. You might want to add the tag [riemann-zeta] to your question as well.

2 votes
0 answers
75 views

Riemann's Zeta Function Page 17: note $\psi(x)=\sum_{n=1}^{+\infty}e^{-n^{2}\pi x}$ \begin{equation} \xi(1/2+ti)=4\int_{1}^{+\infty}\frac{d[x^{3/2}\psi^{\prime}(x)]}{dx}x^{-1/4} \cos\left(\frac{t\ln x}...
psifunction's user avatar
2 votes
0 answers
92 views

This is related to P. Deligne's paper La conjecture de Weil I, (5.8 b) (pp. 293) and the proof of (7.1) (p. 300). In (5.8) the author shows that there is a short exact sequence \begin{equation*} 0\...
The Thin Whistler's user avatar
3 votes
0 answers
181 views

Let $$\pi(x)=\sum\limits_{p\le x} 1\tag{1}$$ be the prime-counting function and $$\rho=\alpha+i \gamma\tag{2}$$ represent a non-trivial zeta zero in the critical strip. This question is about formula ...
Steven Clark's user avatar
  • 9,346
19 votes
1 answer
2k views

I've seen it reported that we've found all of the nontrivial zeros to the Riemann zeta function up to some large height, and that all of them have real part $1/2$; i.e. a counterexample would need ...
HiddenBabel's user avatar
0 votes
1 answer
74 views

Let $s=\frac12+iz$ be a non-trivial zero of the Riemann Zeta function $\zeta(s)$. Let $f(s,a)=\frac12+iaz$ where $s=\frac12+iz$ be the $a$ complex conjugate of $s$. Eg: $f(s,1)=s$ and $f(s,-1)=\...
Turbo's user avatar
  • 6,341
-2 votes
1 answer
84 views

Let $s=\frac12+iz$ be a non-trivial zero of the Riemann Zeta function $\zeta(s)$. Would the complex conjugate $\overline s$ satisfy $\zeta(\overline s)=0$? If not generally would they ever satisfy the ...
Turbo's user avatar
  • 6,341
4 votes
1 answer
207 views

First of all, please note that I'm just a curious amateur, and the goal of this question is purely out of curiosity rather than directed research. For a reason I don't really understand, it seems ...
GB1200's user avatar
  • 61
2 votes
1 answer
113 views

I am having difficulties into understanding the last part of the proof of Hasse Corollary of the Riemann hypothesis over finite fields: Let $g \in \mathbb{Z}[X]$ be a cubic polynomial with no multiple ...
CarloReed's user avatar
3 votes
0 answers
148 views

I came to know that $$\frac{\pi\left(x\right)-\text{Li}\left(x\right)}{\frac{\sqrt{x}}{\log x}}=-1-\sum _{\ \zeta \left(\frac{1}{2}+i\gamma \right)=0}^{ }\frac{x^{i\gamma }}{\frac{1}{2}+i\gamma }+O\...
Random guy's user avatar
2 votes
1 answer
263 views

I have been studying the Riemann Hypothesis for some time and I have recently stumbled upon the book "The Riemann Hypothesis A Resource for the Afficionado and Virtuoso Alike" (https://link....
Zackury's user avatar
  • 185
2 votes
0 answers
128 views

We know, assuming eta function, that $$\eta(x) =\sum_{n=1}^{\infty}(-1)^{1-n}\frac{1}{n^{x}}$$ and $$\eta (x)=(1-2^{1-x})\zeta (x)$$ so we have zeros of this function at $x=1$ for $$\frac{2\pi k}{\ln\...
Freak's user avatar
  • 37
0 votes
0 answers
63 views

For example, Riemann hypothesis is absolute and that's why we can't apply forcing to obtain independence result. But is negation of Riemann hypothesis also absolute? That is, if ¬RH is true in ZFC, ...
ano 523's user avatar
  • 21
3 votes
0 answers
202 views

I’m honestly in a bit of shock after coming across this fascinating rule from the Clay Mathematics Institute's official problem guidelines: "If, alternatively, the counterexample shows that the ...
ZetaGoddess's user avatar
1 vote
1 answer
106 views

After reading it I have no clear idea if proof from Guy Robin "Sur l’ordre maximum de la fonction somme des diviseurs" or in other similars related to Merten's Theorems (2nd and 3rd) does ...
24th_moonshine's user avatar
3 votes
1 answer
178 views

Let $(X_i)_{i \in \Bbb N}$ be a sequence of independent RV's with zero means $\Bbb E[X_i]=0$ and let $(b_i)_{i \in \Bbb N}$ be an increasing sequence of positive numbers satisfying $\sum_i \Bbb E[X_i^...
user267839's user avatar

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