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From its description I thought that the normalizations of the directions d_i of the semi-axes did not matter when using the Ellipsoid function. Indeed, the following two commands give the same output:

Needs["MultivariateStatistics`"]; Graphics[Ellipsoid[{0, 0}, {1, 1}, {{0, 1}, {1, 0}}], Axes -> True] Graphics[Ellipsoid[{0, 0}, {1, 1}, {{0, 100}, {100, 0}}], Axes -> True]

However, if the normalization of the two directions is different, I get a funny behavior. Basically, the radii are multiplied by the normalization of the first direction vector. Use for example:

Graphics[Ellipsoid[{0, 0}, {1, 1}, {{0, 100}, {1, 0}}], Axes -> True]

Does anyone know what is going on?

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2 Answers 2

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You can find the details of how the third argument of Ellipsoid is processed by inspecting the code which is available in the package MultiDescriptiveStatistics.m.

nb = NotebookOpen[ToFileName[{$InstallationDirectory, "AddOns", "Packages", "MultivariateStatistics"}, "MultiDescriptiveStatistics.m"]]; NotebookFind[nb, "Ellipsoid[mu_?VectorQ, r_?VectorQ, dir_?MatrixQ]"]

enter image description here

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You have to write the parameters like this (see documentation):

Graphics[Ellipsoid[{0, 0}, {100, 200}, {0, 1}], Axes -> True]

enter image description here

Parameter 1: Center
Parameter 2: Radii
Parameter 3: Direction

EDIT

If you work with vectors, please consider:

Show[Graphics[Ellipsoid[{0, 0}, {100, 200}, {1, 0.5}], Axes -> True], Graphics@Arrow[{{-100, 200}, {100, -200}}]]

enter image description here

I'm afraid you have to do some arithmetic to get {100, 200}, {1, 0.5} from {{-100, 200}, {100, -200}}

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  • $\begingroup$ thanks, but i need to use vectors as directions (which may not be aligned with the axes) $\endgroup$ Commented Jun 26, 2014 at 14:12
  • $\begingroup$ Did you find this syntax in the documentation? Where? Also, how do you generalize this syntax to three dimensions? $\endgroup$ Commented Jun 26, 2014 at 16:57
  • $\begingroup$ @Valerio link $\endgroup$ Commented Jun 26, 2014 at 18:19

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