Partition With Offset

Question

I have the following two lists:

{a,b,c,d,e,f} and {x,y,z}

and would like to use Partition to create groups of the form:

{a,x}, {b,y}, {c, z}

My first approach is to use:

list1 = {a,b,c,d,e} list2 = {x,y,z} flat = Flatten[{list1, list2}]

The output of which is a single list that I intended to use Parition to create the list of pairs.

So, if I try Partition

Partition[flat, 2, 5}

The result is: {{a, b}, {x, y}}

Not the desired result, but I can't find the right parameters of Partition to generate the correct list of pairs.

I can drop the the final elements of list1 based on the length of list2 and then use Transpose.

Just curious if Partition can get to the same result.

Are you aware of this? Flatten[{{a, b, c, d, e, f} , {x, y, z}}, {2}] — Mr.Wizard
– Mr.Wizard, Commented Mar 13, 2020 at 14:21

Mr.Wizard · Accepted Answer · 2020-04-05 05:57:32Z

I think a solution using solely Partition does not exist, but with Transpose:

list1 = {a, b, c, d, e}; list2 = {x, y, z}; flat = Flatten[{list1, list2}]; Partition[flat, 3, 5]\[Transpose]

{{a, x}, {b, y}, {c, z}}

Partition[flat, 6, 1][[All, {1, -1}]]

{{a, x}, {b, y}, {c, z}}

Perhaps Riffle is of interest too:

list1 ~Riffle~ list2 ~Partition~ 2

{{a, x}, {b, y}, {c, z}, {d, x}}

And Flatten has a ragged form:

Flatten[{list1, list2}, {2}] % // Cases[{_, _}]

{{a, x}, {b, y}, {c, z}, {d}, {e}} {{a, x}, {b, y}, {c, z}}

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