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1 vote
1 answer
17 views

Consider the polynomial $f(x)= x^2+1$. Can you prove that there are there infinitely many integers $x$ such that $f(x)$ has no prime divisor congruent to $1 \bmod 3$? Obviously the prime divisors are ...
Euro Vidal Sampaio's user avatar
2 votes
0 answers
12 views

Let $\Omega\subset\mathbb{R}^n$ be a bounded Euclidean domain with Lipschitz (possibly smoother) boundary and consider an Elliptic Dirichlet problem of the form \begin{align} \mathcal{L} u + \alpha(x,...
AB_IM's user avatar
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3 votes
0 answers
66 views

Let $\Gamma$ be a torsion free Zariski-dense discrete subgroup of $\operatorname{SL}_3(\mathbb{R})$. Then one can show that the cohomological dimension of $\Gamma$ is less or equal to 5. The equality ...
M. Han's user avatar
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0 votes
0 answers
130 views

I am still now stumped on deriving the series equivalence $$\zeta(3)=\frac{5}{2}\sum_{n=1}^{\infty}\frac{(-1)^{n-1}}{n^3\binom{2n}{n}}$$ Like even I did not get the series for $\frac1{n^2}$ mentioned ...
vidyarthi's user avatar
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2 votes
1 answer
73 views

$\DeclareMathOperator{\A}{\mathcal{A}}\DeclareMathOperator{\C}{\mathcal{C}}\DeclareMathOperator{\coker}{coker}$Let $\A$ be a an abelian category and let $\C$ be an additive category such that $\C$ is ...
psl2Z's user avatar
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0 votes
0 answers
23 views

Suppose $\Omega \subsetneqq S^{n}$ is a connected open domain and carries the complete metric $ \tilde{g} = u^{\frac{4}{n-2}}\, g_{\mathrm{st}}\!\mid_{\Omega}, $ where $u : \Omega \to \mathbb{R}^+$ is ...
Jialong Deng's user avatar
  • 2,279
3 votes
1 answer
61 views

Let $V$ be the standard $2g$-dimensional representation of $\mathrm{Sp}(V)$ (with $g \ge 1$), and for each $m \ge 1$ let $S^m V$ denote the $m$-th symmetric power. Consider the Schur functor $S^{(2,1)}...
kindasorta's user avatar
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-5 votes
0 answers
140 views

I have an economics and statistics background. However, I often find the two subjects too narrow in the sense that they employ very specific sets of mathematics. I would like to explore something more ...
Jason Chun's user avatar
0 votes
0 answers
150 views

The following material is quoted from A Crèche Course in Model Theory by Domenico Zambella, Section 15.3. $\mathcal{U}$ is how we denote the Monster model. For every $a\in\mathcal{U}^{x}$ and $b\in\...
centa's user avatar
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3 votes
0 answers
60 views

The Eilenberg Watts theorem tells us that every $k$-linear right-exact cocontinuous functor $F:\text{Rep}(A)\to \text{Rep}(B)$ comes from tensoring with a bimodule. In particular if $F$ commutes with ...
Simon Lentner's user avatar
1 vote
0 answers
33 views

In Theorem 2.1 of this paper, Tam and Yu prove that: if a Kähler manifold $M$ has ${\rm bisec}\geq2k$, $p\in M$ and $r(x)=d(p,x)$, then for any unit vector $v\in T_xM$ perpendicular to $\nabla r$, we ...
HeroZhang001's user avatar
1 vote
1 answer
134 views

For a smooth Fano variety $Z$, let $X$ be the total space of its canonical bundle. Let $\operatorname{Coh}_Z(X)$ be the category of coherent sheaves that support on $Z$ set-theorically. How to show ...
math f1sh's user avatar
7 votes
1 answer
199 views

Let $M^n$ be a closed smooth $n$-manifold with $n \ge 3$. Suppose its universal cover is diffeomorphic to $\widetilde{M} \cong S^{n-1} \times \mathbb{R},$ where $S^{n-1}$ carries the standard smooth ...
Jialong Deng's user avatar
  • 2,279
-2 votes
0 answers
30 views

I’m implementing a version of the Levinson recursion that should handle sub-singular Hermitian Toeplitz matrices. My code works perfectly when the Toeplitz entries are real, but it fails as soon as ...
user1715974's user avatar
6 votes
1 answer
159 views

Let $G$ be a finite perfect group with non-trivial center. I am trying to show that a Sylow $2$-subgroup of $G$ is non-abelian. I think one needs to use transfer homomorphisms here. However I can not ...
cryptomaniac's user avatar

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