try to set GPIO.output(x, LOW) but connected LED still lights

Question

I try to make a LED light up with the code

 import RPi.GPIO as GPIO import time GPIO.setmode(GPIO.BOARD) GPIO.setup(16, GPIO.IN, pull_up_down=GPIO.PUD_DOWN) GPIO.setup(18, GPIO.OUT) while (var==1): GPIO.output(18,GPIO.LOW) GPIO.cleanup()

as illustrated in the figure, the pin 18 serves to light up a LED or switch it Down but when I try with sudo python3 this script I see that the LED is lighten just a bit. Only if I connect my transistor base to the ground, I see that the LED is off completely I conclude that pin 18 is between HIGH and LOW, ont completely LOW... why?

the LED is incorrectly oriented ... it will not light even if the transistor is bridged — jsotola
– jsotola, Commented Apr 5, 2021 at 23:55

Milliways · Accepted Answer · 2021-04-05 00:39:49Z

It is unclear exactly what you have done (list full code & connections). What is R_US

The fundamental problem is your circuit.

Using an emitter follower is POOR practice; it will attempt to put 2.7V across the LED when ON, overloading the GPIO with unpredictable results. You have shown the LED connected in reverse.

Try a more conventional circuit; the LED & resistor in series would form the load. See https://elinux.org/RPi_GPIO_Interface_Circuits

NOTE with normal LED you can drive (up to 16mA) directly from the GPIO.

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