ASP.NET MVC Controller.Json DateTime Serialization vs NewtonSoft Json DateTime Serialization

I finally figured out what to do.
I will switch my project to ISO 8601 DateTime format. Serialization is done nicely with JSON.net, just by decorating the datetime property on the object with JsonConverter attribute.

 public class ComplexObject { [JsonProperty] public string ModifiedBy { get; set; } [JsonProperty] [JsonConverter(typeof(IsoDateTimeConverter))] public DateTime Modified { get; set; } ... } 

To return serialized object to the client ajax call I can do:

 return Json(JsonConvert.SerializeObject(complexObjectInstance)); 

and on the client:

 jsObject = JSON.parse(result) 

Now I am thinking it would be probably simple to override default ASP.NET MVC default JSON serializer to us Newtonsoft JSON.net ISO 8601 serialization, and yes principle should be similar to this thread: Change Default JSON Serializer Used In ASP MVC3.

In the WebApiConfig set:

config.Formatters.Remove(config.Formatters.XmlFormatter); //config.Formatters.JsonFormatter.SupportedMediaTypes.Add(new MediaTypeHeaderValue("text/html")); config.Formatters.JsonFormatter.SupportedMediaTypes.Add(new MediaTypeHeaderValue("application/json")); config.Formatters.JsonFormatter.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver(); config.Formatters.JsonFormatter.SerializerSettings.Formatting = Newtonsoft.Json.Formatting.Indented; config.Formatters.JsonFormatter.SerializerSettings.DateFormatHandling = Newtonsoft.Json.DateFormatHandling.IsoDateFormat; config.MapHttpAttributeRoutes(); 

In the ApiController return this:

return Request.CreateResponse(HttpStatusCode.OK, obj); 

Good Luck CAhumada

If you dont want to dig in to the Parsing thing than simply convert your date in to the string than parse it with the JSON.

for example

return Json(DateTime.Now.ToString("your date format if you want to specify")); 

It returns Server Date Format. You need to define your own function.

function jsonDateFormat(jsonDate) { // Changed data format; return (new Date(parseInt(jsonDate.substr(6)))).format("mm-dd-yyyy / h:MM tt"); 

};