I have a complex object that I want to be able to pass into a std::ostringstream with the << operator just like a string or int. I want to give the ostringstream the object's unique id (int) and/or name (string). Is there an operator or method I can implement in my class to allow this to work?
1 Answer
Define an operator overload in the same namespace as your class:
template<typename charT, typename traits> std::basic_ostream<charT, traits> & operator<< (std::basic_ostream<charT, traits> &lhs, Your_class const &rhs) { return lhs << rhs.id() << ' ' << rhs.name(); } If the output function needs access to private members of your class then you can define it as a friend function:
class Your_class { int id; string name; template<typename charT, typename traits> friend std::basic_ostream<charT, traits> & operator<< (std::basic_ostream<charT, traits> &lhs, Your_class const &rhs) { return lhs << rhs.id << ' ' << rhs.name; } }; Note that this does not result in a member function, it's just a convenient way to declare and define a friend function at once.
1 Comment
AlwaysLearning
The
traits template parameter has a default value, so it can be skipped.
ostringstream?