Java - How to get the name of a file from the absolute path and remove its file extension?

Question

I have a problem here, I have a String that contains a value of C:\Users\Ewen\AppData\Roaming\MyProgram\Test.txt, and I want to remove the C:\Users\Ewen\AppData\Roaming\MyProgram\ so that only Test is left. So the question is, how can i remove any part of the string.

Thanks for your time! :)

Are you asking this in a more general direction of how to remove parts of a string, or specifically for strings containing file paths? — garbagecollector
– garbagecollector, Commented Aug 10, 2012 at 0:02

Community · Accepted Answer · 2017-05-23 12:07:59Z

6

If you're working strictly with file paths, try this

String path = "C:\\Users\\Ewen\\AppData\\Roaming\\MyProgram\\Test.txt"; File f = new File(path); System.out.println(f.getName()); // Prints "Test.txt"

Thanks but I also want to remove the .txt

OK then, try this

String fName = f.getName(); System.out.println(fName.substring(0, fName.lastIndexOf('.')));

Please see this for more information.

edited May 23, 2017 at 12:07

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answered Aug 9, 2012 at 23:59

mre

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4 Comments

Ewen Over a year ago

Thanks but I also want to remove the .txt

salezica Over a year ago

@mre haha that is exactly what I tried to avoid with my answer D:

Rosdi Kasim Over a year ago

@mre, fName.substring(fName.lastIndexOf('.')) is suffice.

fchen Over a year ago

To avoid using File(), use: path.substring( path.lastIndexOf('\\')+1, path.lastIndexOf('.') )

salezica · Accepted Answer · 2012-08-10 00:09:02Z

1

The String class has all the necessary power to deal with this. Methods you may be interested in:

String.split(), String.substring(), String.lastIndexOf()

Those 3, and more, are described here: http://docs.oracle.com/javase/1.4.2/docs/api/java/lang/String.html

Give it some thought, and you'll have it working in no time :).

answered Aug 10, 2012 at 0:09

salezica

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4 Comments

mre Over a year ago

If you're working strictly with file paths, I think it's easier to just use the File class rather than String.split to parse the file name.

salezica Over a year ago

Easier it is, but I don't think we should give such a shortcut (which involves extra objects, and dealing with a type semantically outside the immediate domain of the problem, which is strings) to someone that would ask this question in the first place :) What will he do when it's : and not / delimiting his paths?

mre Over a year ago

Well, you're right in that my solution isn't flexible, nor elegant, but it is concise! :D

salezica Over a year ago

Oh no I think your approach is way more elegant than mine (concise = elegant most of the time!). I would actually do it your way myself, it's just not very educational :(

Felix Bohnacker · Accepted Answer · 2016-05-12 09:21:16Z

I recommend using FilenameUtils.getBaseName(String filename). The FilenameUtils class is a part of Apache Commons IO.

According to the documentation, the method "will handle a file in either Unix or Windows format". "The text after the last forward or backslash and before the last dot is returned" as a String object.

String filename = "C:\\Users\\Ewen\\AppData\\Roaming\\MyProgram\\Test.txt"; String baseName = FilenameUtils.getBaseName(filename); System.out.println(baseName);

The above code prints Test.

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