Directory command line argument

Question

I'm having trouble taking in a path where to run the script as a command line argument, test is it exists, then changing to that path to perform work. Here what I'm trying:

#!/bin/bash scriptpath=$1 if [ $# -lt 1 ] then echo "Usage: script.sh <directory_name>" fi if [ -d scriptpath ] then # work...... else echo "Directory does not exist" fi

Even if the directory exists flow falls to the else statement — Connor Black
– Connor Black, Commented Aug 10, 2012 at 21:26

ruakh · Accepted Answer · 2012-08-10 21:25:20Z

Change this:

if [ -d scriptpath ]

to this:

if [ -d $scriptpath ]

Also, I recommend making use of "", so that your script still behaves properly when the argument contains weird characters. (Unix allows spaces, newlines, asterisks, even control characters inside filenames.) So:

scriptpath="$1" ... if [ -d "$scriptpath" ]

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