Make a django template object iterable

Question

I have a dictionary with a number of characteristics:

sort_options = SortedDict([ ("importance" , ("Importance" , "warning-sign" , "importance")), ("effort" , ("Effort" , "wrench" , "effort")), ("time_estimate" , ("Time Estimate" , "time" , "time_estimate")), ])

I also have a list of actions as a query result. Each action has these attributes; In my template, I can call {{ action.effort }} or {{ action.time_estimate }} and get a result.

I'm iterating through my sort_options to populate twitter bootstrap icons:

{% for key, icon in sort_options.items %} <i class="icon-{{ icon.1 }}"></i> {% endfor %}

But I also want to display the action value for each of these attributed. Essentially, something like:

{% for key, icon in sort_options.items %} <i class="icon-{{ icon.1 }}"></i> {{ action.key }} {% endfor %}

Where key would resolve to "importance" or "effort". I know this doesn't work. So I was trying to leverage the solution presented in this question.

The solution proposed a template filter:

def hash(h,key): if key in h: return h[key] else: return None register.filter(hash) {{ user|hash:item }}

Where the question used a dictionary that looked like so:

{'item1': 3, 'name': 'username', 'item2': 4}

I tried the following:

{% for key, icon in sort_options.items %} <i class="icon-{{ icon.1 }}"></i> {{ action|hash:key }} {% endfor %}

But got an error:

Caught TypeError while rendering: argument of type 'Action' is not iterable

I believe this is because the template filter is getting just one attribute of the object (likely the name) as opposed to the whole dictionary:

[<Action: Action_one>, <Action: Task_two>...]

Is there a way to force the template to pass the full object to the template tag?

Please make sure that you mean a template tag but not a template filter. — sergzach
– sergzach, Commented Aug 13, 2012 at 19:19
Ignore that other question. Exactly what are you trying to achieve? — Daniel Roseman
– Daniel Roseman, Commented Aug 13, 2012 at 19:23
Apologies for being too hasty with the question. It is greatly clarified above — Ed.
– Ed., Commented Aug 13, 2012 at 19:52
For future reference, mentioning that you're iterating over actions and then iterating over sort_options for each action would have been handy. Finally, something that looks like [.., ..] is a list, not a dictionary. Your "whole dictionary" is better described as a "list of Action objects`. — supervacuo
– supervacuo, Commented Aug 13, 2012 at 20:11
Can't u just calculate those 'action.key's in your views, and then try sending them as dictionaries to the templates so u won't have to find action.key in your templates ? — user633784
– user633784, Commented Aug 13, 2012 at 20:15

Community · Accepted Answer · 2017-05-23 12:09:49Z

I think I finally get it. You want the equivalent of

getattr(action, key)

in your template. This answer describes the getattribute templatetag you'd need to do so.

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