greping for a value != *.file extension

Question

Not 100% on how to go about this.

Basically my app creates two file outputs.

file file.ext

when searching through the directory it always returns both files. I wish only to work with

file

how can I do a grep for just the file? Or is grep even the correct command?

!grep *.ext

pseudo code ^

Stephane Rouberol · Accepted Answer · 2012-08-31 08:55:14Z

1

Why not just:

grep foobar file

or if you want to search your directory

find . -name 'file' | xargs -r grep boofar

answered Aug 31, 2012 at 8:55

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Comments

pavel · Accepted Answer · 2012-08-31 08:53:25Z

You can try using grep 'file$', i.e. select lines ending with file and nothing after that. Alternatively you can use grep -v to invert results.

# (echo "file"; echo "file.txt") | grep file$ file # (echo "file"; echo "file.txt") | grep -v .ext file

Šimon Tóth · Accepted Answer · 2012-08-31 08:54:15Z

I have no idea what you are trying to do with grep, but if you want to check whether a file exists, you do simply this:

if [ -r /some/path/file ]; then echo "File is readable." fi

Costi Ciudatu · Accepted Answer · 2012-08-31 08:54:27Z

Grep has a -v flag that inverses the meaning (looks for lines that do not contain the pattern):

ls /your/directory | grep -v '\.ext$'

This will exclude every filename ending with .ext.

Akhil Thayyil · Accepted Answer · 2012-08-31 08:55:26Z

0

Try

grep -v option

-v do the inverse match

For details do $ man grep

answered Aug 31, 2012 at 8:55

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William Pursell · Accepted Answer · 2012-08-31 16:45:28Z

To generate a list of all files that do not match a pattern, use -not in find. So you want:

find . -not -name '*.ext'