Catching any webservice exception?

Question

I have a soap @webservice, and a client sending requests as below:

try { // any webservice confniguration here webservice.call(); } catch (Exception e) { System.out.println("ERROR"); }

Now if the connections time out, I'm getting a java.net.socketTimtoutException with stacktrace, plus my error sysouts above. How can I prevent the stacktrace from being printed to console? I don't understand why I ever get it as I'm catching any occuring exception, aren't I?

Somewhere, a try/catch catches the exception, prints it, and then rethrows it. You will have to investigate deeper. — user462963
– user462963, Commented Oct 2, 2012 at 9:59
Try writing other instructions after your try/catch block to see if they are reached like System.out — GingerHead
– GingerHead, Commented Oct 2, 2012 at 10:15
Yes they are. The code continues, somehow the ex is thrown in between, but without me specifiying this... — membersound
– membersound, Commented Oct 2, 2012 at 10:17
It might be the framework printing the exception before throwing it... which class prints the exception? Maybe you can post the whole stacktrace... — home
– home, Commented Oct 2, 2012 at 10:39

GingerHead · Accepted Answer · 2012-10-02 10:22:11Z

Then it's clearly obvious that somewhere in between, a try/catch block catches the exception, prints the stack trace, and then rethrows it. As @WernerVesterås said.
I can advise you to debug the code.

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