Im trying this but doesn't seem to work:
A = {{1,2},{3,4}} A[[1]][[2]] = 5; How could I do that?
Currently I'm doing
list = {3,5}; A[[2]] = list; 
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1 Answer
Your code is right, except for a minuscule error :)
You wrote:
A = {{1, 2}, {3, 4}} A[[1]][[2]] = 5; ^ ^ | This space means multiplication! The correct code is
A = {{1, 2}, {3, 4}} ; A[[1]][[2]] = 5; Usually written as:
a = {{1, 2}, {3, 4}} ; a[[1, 2]] = 5; Remember to start your identifiers with lowercase letters, as capitals are reserved for system's names
2 Comments
abcd
The question didn't actually have a space — it had a line break. SO put it on the same line because it was not wrapped in a code block. So what he originally had should've worked. I'm guessing this is what happened: Since the first line was not terminated, it printed the original contents of A to the notebook. OP took that to mean A has not been updated. If they had evaluated
A again, they would've noticed the change. Either way, TL :)
José D.
a[[1]][[2]] = 5; doesn't work for me (Set::setps: A〚1〛 in assignment of part is not a symbol.), but a[[1,2]] = 5; works fine, thanks for the answer.