Possible Duplicate:
Python decimal range() step value
I have a cycle in C:
for (float i = 0; i < 2 * CONST; i += 0.01) { // ... do something } I need the same cycle in python, but:
for x in xxx not the same.
How can i make it in python?
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4 Answers
You are almost on the line. This is how you do it on a list: -
your_list = [1, 2, 3] for eachItem in your_list: print eachItem If you want to iterate over a certain range: -
for i in xrange(10): print i To give a step value you can use a third parameter, so in your case it would be: -
for i in xrange(2 * CONST, 1): print i But you can only give an integer value as step value.
If you want to use float increment, you would have to modify your range a little bit:-
for i in xrange(200 * CONST): print i / 100.0 
4 Comments
alanmanderson
I suggest range in favor of xrange because range actually creates an array wasting space
MrSil
Thx, you gave me a point how to do that.
Rohit Jain
@MrSil. You're welcome :) You should take the update code. I mistakenly wrote incorrect range in the last code. Corrected now. :)
MrSil
@Rohit Jain already solved my problem, thx.
for i in xrange(200*CONST): i = i/100.0 Comments
Write your own range generator. This helps you deal with non-integer step values with ease, all across your program, solving multiple issues of the same kind. It also is more readable.
def my_range(start, end, step): while start <= end: yield start start += step for x in my_range(1, 2 * CONST, 0.01): #do something answered Oct 27, 2012 at 9:02
Anirudh Ramanathan
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3 Comments
Kos
This looks the most correct; both
range and xrange work on integers and a custom range-like generator allows to work around that. See also stackoverflow.com/questions/477486/…
Dunes
Adding lots of floats together is a recipe for inaccuracy. Following link shows a better way to create a float range: code.activestate.com/recipes/66472
Kos
Yes, that way's nice, and it's easy to turn that function into a generator too.
