Sorting a array of objects based on the value of one of the properties of the objects in javascript [duplicate]

Question

Possible Duplicate:
Sort JavaScript array of Objects based on one of the object’s properties

I have an object which has a property called z:

function building(z) { this.z = z; }

Let's say I create 3 instances of this object:

a = new building(5) b = new building(2) c = new building(8)

These instances are then placed into an array

buildings = [] buildings.push(a) buildings.push(b) buildings.push(c)

The Question

How would I sort this array IN ASCENDING ORDER based on the z property of the objects it contains? The end result after sorting should be:

before -> buildings = [a, b, c] sort - > buildings.sort(fu) after -> buildings = [b, a, c]

lrsjng · Accepted Answer · 2012-10-28 13:12:33Z

5

you can pass a compare-function to .sort()

function compare(a, b) { if (a.z < b.z) return -1; if (a.z > b.z) return 1; return 0; }

then use:

myarray.sort(compare)

here are some docs

answered Oct 28, 2012 at 13:12

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1 Comment

I'm aware of this but the question I have is what would the compare function be? I'm new to using compare functions so would appreciate some help.