How can I create a new folder with Google Drive API in Python?

To create a folder on Drive, try:

 def createRemoteFolder(self, folderName, parentID = None): # Create a folder on Drive, returns the newely created folders ID body = { 'title': folderName, 'mimeType': "application/vnd.google-apps.folder" } if parentID: body['parents'] = [{'id': parentID}] root_folder = drive_service.files().insert(body = body).execute() return root_folder['id'] 

You only need a parent ID here if you want to create folder within another folder, otherwise just don't pass any value for that.

If you want the parent ID, you'll need to write a method to search Drive for folders with that parent name in that location (do a list() call) and then get the ID of that folder.

Edit: Note that v3 of the API uses a list for the 'parents' field, instead of a dictionary. Also, the 'title' field changed to 'name', and the insert() method changed to create(). The code from above would change to the following for v3:

 def createRemoteFolder(self, folderName, parentID = None): # Create a folder on Drive, returns the newely created folders ID body = { 'name': folderName, 'mimeType': "application/vnd.google-apps.folder" } if parentID: body['parents'] = [parentID] root_folder = drive_service.files().create(body = body).execute() return root_folder['id'] 

The mediafile uplaod is needed only if you want to insert content. Since you want only to insert metadata (folders are only metadata), you don't need it. A regular POST with the JSON representing the foder is enough.

You can get the parent ID in several ways :

• searching (file.list end point)
• inserting folder : this returns you a JSON representing the inserted folder, containing its ID
• getting it yourself via the web UI (the ID is contained in the URL of your folder or file) : go to the Web UI, select the folder or file you want, then you can identify the fileId in the URL. ex : https://drive.google.com/#folders/0B8VrsrGIcVbrRDVxMXFWVkdfejQ
  The file Id is the last part of the URL, ie. 0B8VrsrGIcVbrRDVxMXFWVkdfejQ

How to get an FileID programatically :

1. Use the children.list endpoint using a known fileId to get the ids of the children of this known ID.
2. Use the search feature of google drive : files.list endpoint with a q parameter
3. Use aliases : the only one I know in Google Drive is root for the root folder of your Drive.

Using 3. and 1., you can get all the fileIds of your Drive.

I dont know how I can be clearer

def create_folder(header, folder_name, folder_id, drive_id=None): url = 'https://www.googleapis.com/upload/drive/v3/files' file_metadata = { 'name': folder_name, 'mimeType': 'application/vnd.google-apps.folder', 'parents': [folder_id] } file_withmetadata = {"data": ("metadata", json.dumps(file_metadata), "application/json; charset=UTF-8")} param = {"q":"'%s' in parents" %folder_id, "supportsAllDrives":"true"} if drive_id is not None: param['driveId'] = drive_id r = requests.post( url, headers=header, params=param, files=file_withmetadata ) return json.loads(r.text)