from numpy import * f = open('matrix.txt', 'r') x = [] for line in f.readlines(): y = [value for value in line.split()] x.append(y) f.close() x = map(int, x) a = array([x]) Basically, my code is suppose to open the text file and put it into the list x. I then change those values in x into an integer and place that in an array a. Is there a faster way to do this? Btw my code doesn't work.
import numpy as np with open('matrix.txt', 'r') as f: x = [] for line in f: x.append(map(int, line.split())) print x print np.array(x) With matrix.txt containing 3 lines with 4 numbers each:
1 2 3 4 5 6 7 8 9 8 7 6 as above, this prints
[[1, 2, 3, 4], [5, 6, 7, 8], [9, 8, 7, 6]] [[1 2 3 4] [5 6 7 8] [9 8 7 6]] However, as mentioned in a previous answer, consider using numpy.loadtxt. For example, if
print np.loadtxt('matrix.txt')
is added to the program, it also prints out
[[ 1. 2. 3. 4.] [ 5. 6. 7. 8.] [ 9. 8. 7. 6.]] 
dtype when you pass it to np.loadtxt to retrieve integers as it appears that is what OP wants.
print np.loadtxt('matrix.txt', int) or print np.loadtxt('matrix.txt', dtype=int) (after saying import numpy as np)You'll probably do a little better if you use np.loadtxt.
almost there...
the following lines create a list of list which you don't want
y = [value for value in line.split()] x.append(y) because of this the map call would fail
instead of these 2 lines use
x = [int(value) for value in line.split()] 