I have an object literal, where the values of its key are more objects, and one of the keys of the inner objects is named "rank" - and has an floating point value. I want to convert the object literal to an array of the inner objects, sorted by the value of "rank".
Input Object:
{ 452:{ bla:123, dff:233, rank:2 }, 234:{ bla:123, dff:233, rank:1 } }
Output Array:
[ { bla:123, dff:233, rank:1}, { bla:123, dff:233, rank:2 } ] Example:
var data = { foo: { rank: 5 }, bar: { rank: 2 }, baz: { rank: 8 } }; Javascript:
var mappedHash = Object.keys( data ).sort(function( a, b ) { return data[ a ].rank - data[ b ].rank; }).map(function( sortedKey ) { return data[ sortedKey ]; }); That would first sort the inner objects by the value of obj.rank and after that map the containing objects into an Array.
Result: [{rank: 2}, {rank: 5}, {rank: 8}]
Reference: Object.keys, Array.prototype.sort, Array.prototype.map
The above code contains ECMAscript 262 edition 5 code, which is available in all modern browsers. If you want to support legacy browsers as well, you need to include one of the various ES5-Shim libraries.
Iterate over your object's properties, pushing the inner objects into an array, and then sort the array with a custom sort function:
var inputObject = {}, // your object here arr = []; for (var k in inputObject) arr.push(inputObject[k]); arr.sort(function(a,b) { return a.rank - b.rank; }); 
a.rank - b.rank do in the sort method of the array? Thanks.
.sort() lets you pass a function that will be called whenever comparison between two elements in the array is needed - a and b being the two elements. The comparison function needs to return a positive number if a should come after b in the sorted results, a negative number if a should come before b, and 0 if a and b are equal for sort purposes. In this case the elements are objects that have a numeric rank property, so a.rank - b.rank returns an appropriate value.@ sign, you don't need to use it with the username of the person whose answer or question you are commenting under, they'll see your comment without it.