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how to use multiple arguments with a shebang (i.e. #!)?
How can I make a #! statement accept a param with arguments? It seems to be lumping them all together as one param instead of splitting on space as usual.
Take this contrived example:
$ cat /tmp/echo #!/bin/echo -n $ /tmp/echo /tmp/echo$ works great and outputs the filename without a new line at the end. But this one:
$ cat /tmp/echo #!/bin/echo -n hi $ /tmp/echo -n hi /tmp/echo $ kills the -n arg.
One hack I can do is make another shell script that just execs the first script I want with the params I want, but I'd rather not add extra dependancies if I don't need them.
