How to Post Data to a website through win forms c#

Question

I have an api where in I can post some data n submit and then get whether posted data is valid or no. This api redirects to different urls indicating sucess/failure. For ths what I normally do is , within html tags call the destination url and submit the page:

 <form method="post" action="https://web.tie.org/verify.php" name="main"> <table width="100%" border="0" cellpadding="0" cellspacing="0" align="center" valign="top"> <tr> <td class="normal">&nbsp;</td><td class="normal"><input type='text' class='text' name='Email' value='[email protected]' size='15' maxlength='35'></td> </tr> </table> </form> <script language='javascript'> document.forms[0].submit(); </script>

Is there a way to post data directly through winforms c#. I want to be able to access the success/failure url after post and get the query string of the redirected site.

With Reference to enter link description here I have tried posting but I need the result query string.

Right now I can achieve this by:

webBrowser1.Url = new Uri("C:\\Documents and Settings\\Admin\\Desktop\\calltie.html"); webBrowser1.Show();

Peyman Mehrabani · Accepted Answer · 2012-12-17 11:30:59Z

7

Yes , you can use WebClient class.

public static string PostMessageToURL(string url, string parameters) { using (WebClient wc = new WebClient()) { wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded"; string HtmlResult = wc.UploadString(url,"POST", parameters); return HtmlResult; } }

Example:

PostMessageToURL("http://tempurl.org","query=param1&query2=param2");

answered Dec 17, 2012 at 11:30

Peyman Mehrabani

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5 Comments

Peyman Mehrabani Over a year ago

PostMessageToURL method return the result :)

Pavitar Over a year ago

My PostMessageToURL("tempurl.org","query=param1&query2=param2"); in turn redirects to: query=param1 and appends to that query string. I need the redirected querys tring to pull out activated status. For eg. on sucess it will redirect to param1?valid=yes&exp=a . I want to know what is valid and exp equalt to

Justin Harvey Over a year ago

@Pavitar, see my updated answer below, you need to pull out the responseUri. I am not sure WebClient gives you enough detail to read the headers like this.

Peyman Mehrabani Over a year ago

It's depends on how requested url redirect to new page.by calling javascript function? 304 method o set location to header?

Pavitar Over a year ago

This FieldInfo responseField = webclient.GetType().GetField("m_WebResponse", BindingFlags.Instance | BindingFlags.NonPublic); did the trick. :)

Justin Harvey · Accepted Answer · 2012-12-17 11:47:28Z

Absolutely, take a look at WebRequest, here is a full example

http://msdn.microsoft.com/en-us/library/debx8sh9.aspx

You can then do this kind of thing

UriBuilder uriBuilder = new UriBuilder(url); HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uriBuilder.Uri); request.Method = "POST"; request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = bytesToPost.Length; using(Stream postStream = request.GetRequestStream()) { postStream.Write(bytesToPost, 0, bytesToPost.Length); postStream.Close(); } HttpWebResponse response = (HttpWebResponse )request.GetResponse(); string url = response.ResponseUri

and the last line will give you the URL (success/fail) you are after

Sunny · Accepted Answer · 2012-12-19 09:17:28Z

I am currently working on it .. and this is running code try it..

HttpWebRequest req = (HttpWebRequest)WebRequest.Create("www.linktoposton.php"); req.Method = "POST"; byte[] byteArray = Encoding.UTF8.GetBytes(content); req.ContentType = "application/x-www-form-urlencoded"; req.ContentLength = byteArray.Length; Stream dataStream = req.GetRequestStream(); dataStream.Write(byteArray, 0, byteArray.Length); WebResponse response = req.GetResponse(); dataStream = response.GetResponseStream(); StreamReader reader = new StreamReader(dataStream); string responseFromServer = HttpUtility.UrlDecode(reader.ReadToEnd()); reader.Close(); dataStream.Close(); response.Close(); Application.DoEvents(); // optional

Just change url in Httpwebrequest ("www.linktoposton.php" to the link you want to send)

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