is there a way to have a default Object for parameters in C++ functions? I tried
void func(SomeClass param = new SomeClass(4)); and it worked. However how would I am I supposed to know wheter I have to free the allocated memory in the end? I would like to do the same without pointers, just an Object on the stack. is that possible?
void func(SomeClass param = new SomeClass(4)); This can't work because new returns a pointer
void func(SomeClass param = SomeClass(4)); should work and the object doesn't need to be freed.
SomeClass has a constructor that takes SomeClass*. I admit that is unlikely, and I use the word "work" very loosely.
You almost had it but you don't need the new keyword.
void func(SomeClass param = SomeClass(4)); This method has the advantage over using new in that it will be automatically deleted at the end of a call so no memory management is needed.
An alternative is to use shared pointers.
You could use overloading:
void func(const SomeClass&) const; void func() const { SomeClass* param = new SomeClass(4); func(param); delete param; } 
SomeClass param = new SomeClass(4); does not work as new returns a pointer.
void func(SomeClass param = SomeClass(4));. Your function will receive SomeClass object by value and will destroy it automatically after the function callnew SomeClass(4)returning a pointer to SomeClass while the function expect an instance. but without thenewthere is no problem. +1 since I never thought of trying this before.SomeClass( void * )There's a train-wreck waiting to happen.