Java StringTokenizer

Question

I have the following input (11,C) (5,) (7,AB) I need to split them into 2 part for each coordinates. So my intarray should have 11, 5, 7 and my letter array should have C,,AB

But when I try using stringtokenizer, I only get my intarray should have 11, 5, 7 and my letter array should have C,AB

Is there any way I could get the empty part of (5,)? Thank you.

Vector<String> points = new Vector<String> (); String a = "(11,C) (5,) (7,AB)"; StringTokenizer st = new StringTokenizer(a, "(,)"); while(st.hasMoreTokens()) { points.add(st.nextToken()); } } System.out.println(points);

Edited my post to show the codes. i only got 11, C, 5, 7, AB I need to get 11, C, 5, , 7, AB — mikey
– mikey, Commented Feb 6, 2013 at 10:20

Mikhail Vladimirov · Accepted Answer · 2013-02-06 10:39:42Z

List <Integer> digits = new ArrayList <Integer> (); List <String> letters = new ArrayList <String> (); Matcher m = Pattern.compile ("\\((\\d+),(\\w*)\\)").matcher (string); while (m.find ()) { digits.add (Integer.valueOf (m.group (1))); letters.add (m.group (2)); }

Igor K · Accepted Answer · 2013-02-06 10:36:23Z

Must be like this

String[] values = a.split("\\) \\("); String[][] result = new String[values.length][2]; for (int i = 0; i < values.length; i++) { values[i] = values[i].replaceAll("\\(|\\)", "") + " "; result[i] = values[i].split("\\,"); System.out.println(result[i][0] + " * " + result[i][1]); }

result will contain coordinate pairs.

Achintya Jha · Accepted Answer · 2013-02-06 10:53:22Z

public static void main(String[] args) { String s = "(11,C), (5,) ,(7,AB)"; ArrayList<String> name = new ArrayList<String>(); ArrayList<Integer> number = new ArrayList<Integer>(); int intIndex = 0, stringIndex = 0; String[] arr = s.split(","); for (int i = 0; i < arr.length; i++) { String ss = arr[i].replace("(", ""); ss = ss.replace(")", ""); boolean b = isNumeric(ss); // System.out.println( Arrays.toString(arr)); if (b) { int num = Integer.valueOf(ss.trim()).intValue(); number.add(num); } else name.add(ss); } System.out.println(name); System.out.println(number); } public static boolean isNumeric(String str) { try { double d = Double.parseDouble(str); } catch (NumberFormatException nfe) { return false; } return true; }

Try this: I have slightly changed the input from "(11,C) (5,) (7,AB)" to "(11,C), (5,) ,(7,AB)" .

Output:

[C, , AB] [11, 5, 7]

alepuzio · Accepted Answer · 2013-02-06 10:56:34Z

Brutal coding, in raw level:

List<String> points = new ArrayList<String> (); String source= "(11,C) (5,) (7,AB)"; StringTokenizer deleteLeft = new StringTokenizer(source, "("); while(deleteLeft.hasMoreTokens()) { StringTokenizer deleteRight = new StringTokenizer(deleteLeft.nextToken(), ")"); points.add(deleteRight.nextToken()); } System.out.println(points); }

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