How to print what a bash script is actually running?

Question

I am trying to make a bash script which will:

Add all changes to git
Commit with a message I pass to the bash script
Push it to the repo

I am trying to do this with:

m=\"$*\" git add -A echo git commit -m $m git push

However, I am getting errors saying error: pathspec 'Q2,' did not match any file(s) known to git. for everything word I pass to the script.

How can I see what bash it actually doing? When I put echo in front of the offending line (which I presume is the commit) I get a correctly form command. If I put it in to the terminal, I runs find.

choroba · Accepted Answer · 2013-02-16 20:13:31Z

To see what bash is doing, add -xv options to the shebang line:

#!/bin/bash -xv

The problem is probably the quoting. m=\"$*\" does not do what you want. $m is still split into several words if it contains whitespace, just the first word starts with a doublequote and the last word ends in a doublequote.

Rather, change the offending line to

git commit -m "$m"

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