0

I was wondering if someone knows what the best method would be to extract a link from another link , Here's an example:

If I have links in the following format:

http://www.youtube.com/watch?v=35HBFeB4jYg OR http://it.answers.yahoo.com/question/index?qid=20080520042405AApM2Rv OR https://www.google.it/search?q=rap+tedesco&aq=f&oq=rap+tedesco&aqs=chrome.0.57j62l2.2287&sourceid=chrome&ie=UTF-8#hl=en&sclient=psy-ab&q=migliori+programatori&oq=migliori+programatori&gs_l=serp.3..0i19j0i13i30i19l3.9986.13880.0.14127.14.10.0.4.4.0.165.931.6j4.10.0...0.0...1c.1.7.psy-ab.tPmiWRyUVXA&pbx=1&bav=on.2,or.r_cp.r_qf.&fp=ffc0e9337f73a744&biw=1280&bih=699

How would I go about extracting only the web pages like so: 

http://www.youtube.com http://it.answers.yahoo.com https://www.google.it

I was wondering if and what regular expression I could use with PHP to achieve this, also are regular expressions the way to go?

Improve this question

3 Answers 3

Reset to default
2

There is a PHP function for parsing URLs: parse_url

$url = 'http://it.answers.yahoo.com/question/index?qid=20080520042405AApM2Rv'; $p = parse_url($url); echo $p["scheme"] . "// . "$p["host"];
Improve this answer
Sign up to request clarification or add additional context in comments.

Comments

1

Use function parse_url.

$link = "https://www.google.it/search?q=rap+tedesco"; $parseUrl = parse_url($link); $siteName = $parseUrl['scheme']."://". $parseUrl['host'];

Using Regexp.

preg_match('@http(s?)://([\w]+\.){1}([\w]+\.?)+@',$link,$matches); echo $matches[0];

Codeviper Demo.

Improve this answer

Comments

0

You just want to have the domain of the page, in PHP there exists a function called parse_url that could help

Improve this answer

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.