Check if a given key already exists in a dictionary

Use key in my_dict directly instead of key in my_dict.keys():

if 'key1' in my_dict: print("blah") else: print("boo") 

That will be much faster as it uses the dictionary's O(1) hashing as opposed to doing an O(n) linear search on a list of keys.

You can test for the presence of a key in a dictionary, using the in keyword:

d = {'a': 1, 'b': 2} 'a' in d # <== evaluates to True 'c' in d # <== evaluates to False 

A common use for checking the existence of a key in a dictionary before mutating it is to default-initialize the value (e.g. if your values are lists, for example, and you want to ensure that there is an empty list to which you can append when inserting the first value for a key). In cases such as those, you may find the collections.defaultdict() type to be of interest.

In older code, you may also find some uses of has_key(), a deprecated method for checking the existence of keys in dictionaries (just use key_name in dict_name, instead).

You can shorten your code to this:

if 'key1' in my_dict: ... 

However, this is at best a cosmetic improvement. Why do you believe this is not the best way?

For additional information on speed execution of the accepted answer's proposed methods (10 million loops):

• 'key' in mydict elapsed time 1.07 seconds
• mydict.get('key') elapsed time 1.84 seconds
• mydefaultdict['key'] elapsed time 1.07 seconds

Therefore using in or defaultdict are recommended against get.

I would recommend using the setdefault method instead. It sounds like it will do everything you want.

>>> d = {'foo':'bar'} >>> q = d.setdefault('foo','baz') #Do not override the existing key >>> print q #The value takes what was originally in the dictionary bar >>> print d {'foo': 'bar'} >>> r = d.setdefault('baz',18) #baz was never in the dictionary >>> print r #Now r has the value supplied above 18 >>> print d #The dictionary's been updated {'foo': 'bar', 'baz': 18} 

A dictionary in Python has a get('key', default) method. So you can just set a default value in case there isn't any key.

values = {...} myValue = values.get('Key', None) 

Using the Python ternary operator:

message = "blah" if 'key1' in my_dict else "booh" print(message) 

Use EAFP (easier to ask forgiveness than permission):

try: blah = dict["mykey"] # key exists in dict except KeyError: # key doesn't exist in dict 

See other Stack Overflow posts:

• Using 'try' vs. 'if' in Python
• Checking for member existence in Python

Check if a given key already exists in a dictionary

To get the idea how to do that we first inspect what methods we can call on dictionary.

Here are the methods:

d={'clear':0, 'copy':1, 'fromkeys':2, 'get':3, 'items':4, 'keys':5, 'pop':6, 'popitem':7, 'setdefault':8, 'update':9, 'values':10} 

Python Dictionary clear() Removes all Items Python Dictionary copy() Returns Shallow Copy of a Dictionary Python Dictionary fromkeys() Creates dictionary from given sequence Python Dictionary get() Returns Value of The Key Python Dictionary items() Returns view of dictionary (key, value) pair Python Dictionary keys() Returns View Object of All Keys Python Dictionary pop() Removes and returns element having given key Python Dictionary popitem() Returns & Removes Element From Dictionary Python Dictionary setdefault() Inserts Key With a Value if Key is not Present Python Dictionary update() Updates the Dictionary Python Dictionary values() Returns view of all values in dictionary 

The brutal method to check if the key already exists may be the get() method:

d.get("key") 

The other two interesting methods items() and keys() sounds like too much of work. So let's examine if get() is the right method for us. We have our dict d:

d= {'clear':0, 'copy':1, 'fromkeys':2, 'get':3, 'items':4, 'keys':5, 'pop':6, 'popitem':7, 'setdefault':8, 'update':9, 'values':10} 

Printing shows the key we don't have will return None:

print(d.get('key')) #None print(d.get('clear')) #0 print(d.get('copy')) #1 

We use that to get the information if the key is present or no. But consider this if we create a dict with a single key:None:

d= {'key':None} print(d.get('key')) #None print(d.get('key2')) #None 

Leading that get() method is not reliable in case some values may be None.

This story should have a happier ending. If we use the in comparator:

print('key' in d) #True print('key2' in d) #False 

We get the correct results.

We may examine the Python byte code:

import dis dis.dis("'key' in d") # 1 0 LOAD_CONST 0 ('key') # 2 LOAD_NAME 0 (d) # 4 COMPARE_OP 6 (in) # 6 RETURN_VALUE dis.dis("d.get('key2')") # 1 0 LOAD_NAME 0 (d) # 2 LOAD_METHOD 1 (get) # 4 LOAD_CONST 0 ('key2') # 6 CALL_METHOD 1 # 8 RETURN_VALUE 

This shows that in compare operator is not just more reliable, but even faster than get().

The ways in which you can get the results are:

• if your_dict.has_key(key) Removed in Python 3
• if key in your_dict
• try/except block

Which is better is dependent on 3 things:

1. Does the dictionary 'normally has the key' or 'normally does not have the key'.
2. Do you intend to use conditions like if...else...elseif...else?
3. How big is dictionary?

Read More: http://paltman.com/try-except-performance-in-python-a-simple-test/

Use of try/block instead of 'in' or 'if':

try: my_dict_of_items[key_i_want_to_check] except KeyError: # Do the operation you wanted to do for "key not present in dict". else: # Do the operation you wanted to do with "key present in dict." 

Python 2 only: (and Python 2.7 supports `in` already)

You can use the has_key() method:

if dict.has_key('xyz')==1: # Update the value for the key else: pass 

Just an FYI adding to Chris. B's (best) answer:

d = defaultdict(int) 

Works as well; the reason is that calling int() returns 0 which is what defaultdict does behind the scenes (when constructing a dictionary), hence the name "Factory Function" in the documentation.

A Python dictionary has the method called __contains__. This method will return True if the dictionary has the key, else it returns False.

>>> temp = {} >>> help(temp.__contains__) Help on built-in function __contains__: __contains__(key, /) method of builtins.dict instance True if D has a key k, else False. 

Another way of checking if a key exists using Boolean operators:

d = {'a': 1, 'b':2} keys = 'abcd' for k in keys: x = (k in d and 'blah') or 'boo' print(x) 

This returns

>>> blah >>> blah >>> boo >>> boo 

Explanation

First, you should know that in Python, 0, None, or objects with zero length evaluate to False. Everything else evaluates to True. Boolean operations are evaluated left to right and return the operand not True or False.

Let's see an example:

>>> 'Some string' or 1/0 'Some string' >>> 

Since 'Some string' evaluates to True, the rest of the or is not evaluated and there is no division by zero error raised.

But if we switch the order 1/0 is evaluated first and raises an exception:

>>> 1/0 or 'Some string' Traceback (most recent call last): File "<stdin>", line 1, in <module> ZeroDivisionError: division by zero >>> 

We can use this for pattern for checking if a key exists.

(k in d and 'blah') 

does the same as

if k in d: 'blah' else: False 

This already returns the correct result if the key exists, but we want it to print 'boo' when it doesn't. So, we take the result and or it with 'boo'

>>> False or 'boo' 'boo' >>> 'blah' or 'boo' 'blah' >>> 

You can use a for loop to iterate over the dictionary and get the name of key you want to find in the dictionary. After that, check if it exist or not using if condition:

dic = {'first' : 12, 'second' : 123} for each in dic: if each == 'second': print('the key exists and the corresponding value can be updated in the dictionary')