6

I was looking information about how I can send information using HttpPost method on android, and I always see this:

HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost(posturl); List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("Name","Var1")); params.add(new BasicNameValuePair("Name2","Var2")); httppost.setEntity(new UrlEncodedFormEntity(params)); HttpResponse resp = httpclient.execute(httppost); HttpEntity ent = resp.getEntity();

The problem is that I cant do that, because I have to connect to a resource that receive a String with XML format.

Any idea about how can I send only the String without using a List<nameValuePair>

Improve this question
5
  • How did you get the idea that the above code is related to XML in any way? Plus, your string will need a name when you send it via http, so you'll end up with a name/value pair or a named URL parameter. Commented Apr 18, 2013 at 10:07
  • Ok please clarify what your real problem is. Do you have an XML string and the server cannot accept an XML string value? Then you'll have to tell us what format(s) the server can accept. Or do you think that the name/value pair thingy has something to do with XML? Then the answer is, no, it doesn't. It just rids you of having to fill the POST body yourself. Commented Apr 18, 2013 at 10:21
  • Ok, The server use a javaScrip, on it he read a text you sent it and that text is a XML file or have that format. So i cant use the ValuePairs becasue i have to send only a String. but the methods i saw on internet only use a ValuePairs Array. Now im trying to use Praful Bhatnagar answer. I think it will works Commented Apr 18, 2013 at 11:11
  • Thanks for clarifying. The core question is, how does the POST relate to the JavaScript snippet. You can request data in JavaScript, but can you receive a POST directy? I don't think so. This means that the server receives it before and passes it gets passed to the JavaScript through request variables, In this case, you're wasting your time with Praful's approach. Commented Apr 18, 2013 at 11:22
  • ok, i dont know why but his code work perfectly :) ty too Class. Commented Apr 18, 2013 at 14:14

3 Answers 3

Reset to default
19

Have you tried using StringEntity? Above code can be updated to use StringEntity, Following is the resulting code:

HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost(posturl); httppost.setEntity(new StringEntity("your string")); HttpResponse resp = httpclient.execute(httppost); HttpEntity ent = resp.getEntity();
Improve this answer
Sign up to request clarification or add additional context in comments.

1 Comment

this method works for php function called file_get_contents('php://input') only if we use $_POST['content'] this is not work.why is that?
0

You can use JSON as post parameter. Try referring FlexJson

Improve this answer

1 Comment

i cant use JSON, the server usea a JavaScript file
-1 
// Sending HTTPs Requet to Server try { Log.v("GG", "Sending sever 1 - try"); // start - line is for sever connection/communication HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost( "10.0.0.1/abc.php"); List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1); nameValuePairs.add(new BasicNameValuePair("qrcode", contents)); httppost.setEntity(new UrlEncodedFormEntity( nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); // end - line is for sever connection/communication InputStream is = entity.getContent(); Toast.makeText(getApplicationContext(), "Send to server and inserted into mysql Successfully", Toast.LENGTH_LONG) .show(); // Execute HTTP Post Request response= httpclient.execute(httppost); entity = response.getEntity(); String getResult = EntityUtils.toString(entity); Log.e("response =", " " + getResult); } catch (Exception e) { Log.e("log_tag", "Error in http connection " + e.toString()); }
Improve this answer

1 Comment

This question was answered a long time ago, but your answer is not correct. You are using a list of NameValuePairs and i needed to send only a String without NameValuePairs.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.