We have some objects with properties
class my_object: def __init__(self, type, name): self.type = type self.name = name And a list which contains many object with different type and name values.
What I need is a comprehension which does something like:
if my_object.type == 'type 1' in object_list: object_list.remove(all objects with name == 'some_name') I think what you need is :
if any(obj.type == 'type 1' for obj in object_list): object_list = [obj for obj in object_list if obj.name != 'some_name'] 
I think you are looking for:
object_list = filter(lambda x: x.name != 'some_name', object_list) lambda, you have to figure out what it's doing. I think most people prefer not to look at them if possible arguing that the syntax for the list-comprehension is more elegant and easier to read.if hasattr(my_object,"some_attribute") : doSomething() although in your case I think you want
filter(lambda x:not hasattr(x,"name") or x.name != "some_name",my_list_of_objects) You could do:
def remove_objects(obj_list,*args,**kwargs): for n_count,node in enumerate(obj_list[::]): del_node=False for k,v in kwargs.items(): if hasattr(node,str(k)): if getattr(node,str(k))==v: del_node=True break if del_node: del obj_list[n_count] And use it like:
class HelloWorld(object): lol="haha" my_list_of_objects=[HelloWorld for x in range(10)] remove_objects(my_list_of_objects,lol="haha") 
enumerate.