Split a string in Java with blank removed

Question

What I want to split is the following string:

<java><jquery><comments>

I use the following split method like this:

 String s = "<java><jquery><comments>"; String[] arr = s.split("<|>"); for(String a: arr){ System.out.println(a); }

The output is the following:

java jquery comments

The problem is I don't want the blank line. The size of the array returned from splitting is 6. What I want it to be is 3 letter strings only.

Should I use regular expression to get all letters, or use split like above?

Community · Accepted Answer · 2017-05-23 12:04:58Z

6

Change the split to s.split("[<>]+"). However, there still will be a "" at the beginning of the array, which is due to how split works.

edited May 23, 2017 at 12:04

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answered Apr 30, 2013 at 18:51

zw324

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2 Comments

James Montagne Over a year ago

If you're using [] you would want to remove the |. Otherwise you will split on the | character as well.

zw324 Over a year ago

Thanks, missed that character. Tried to be too fast a gun in the answer:)

anubhava · Accepted Answer · 2013-04-30 19:23:53Z

I think rather than String#split you should Pattern, Matcher and Matcher#find like this:

Pattern p = Pattern.compile("<([^>]+)>"); Matcher m = p.matcher("<java><jquery><comments>"); for (int i=0; m.find(); i++) System.out.printf("MATCHED[%d]: [%s]%n", i, m.group(1));

OUTPUT:

MATCHED[0]: [java] MATCHED[1]: [jquery] MATCHED[2]: [comments]

Romain R · Accepted Answer · 2013-04-30 21:07:16Z

You can also use a StringTokenizer object to split your string according to the correct pattern.

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