Running a script from another python

Question

I just want to have some ideas to know how to do that...

I have a python script that parses log files, the log name I give it as an argument so that when i want to run the script it's like that.. ( python myscript.py LOGNAME ) what I'd like to do is to have two scripts one that contains the functions and another that has only the main function so i don't know how to be able to give the argument when i run it from the second script.

here's my second script's code:

import sys import os path = "/myscript.py" sys.path.append(os.path.abspath(path)) import myscript mainFunction()

the error i have is:

script, name = argv valueError: need more than 1 value to unpack

path = "./myscript.py"? Also, this error most likely originates from myscript.py and not this script considering you don't even use sys.argv in this script — Torxed
– Torxed, Commented May 6, 2013 at 7:28
The error indicates you have 3 arguments in argv but are only unpacking two. Maybe show us more code? (From myscript) — Benjamin Gruenbaum
– Benjamin Gruenbaum, Commented May 6, 2013 at 7:29

Torxed · Accepted Answer · 2013-05-06 07:43:45Z

Python (just as most languages) will share parameters across imports and includes. Meaning that if you do:

python mysecondscript.py heeey that will flow down into myscript.py as well. So, check your arguments that you pass.

Script one

myscript = __import__('myscript') myscript.mainfunction()

script two

import sys def mainfunction(): print sys.argv

And do:

python script_one.py parameter

You should get:

["script_one.py", "parameter"]

As mentioned in a comment on snakes solution. If you need to modify the parameter then do so by supplying mainfunction() with a parameter.

Community · Accepted Answer · 2017-05-23 12:03:26Z

You have several ways of doing it.

>>> execfile('filename.py')

Check the following link:

How to execute a file within the python interpreter?

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