how to do a grep with two parameter (operation AND); that find all lines that containt the word succeeded and failed exactly.
EG:
1. succeeded, failed 2. failed, succeeded 3. failed,failed 4. succeeded, succeeded 5. failed 6. faileds 7. succeeded I need that search return the lines that containt words "succeeded" and "failed", as line 1, 2 and 4
Very simple:
grep succeeded | grep failed Alternatively:
grep 'succeeded.*failed\|failed.*succeeded' The latter approach doesn't scale very well (you end up with P(N, N) subclauses with N words), but can be more flexible when handling things like relative position between the words.
first of all, I think line 4 should not be in result. there is no failed in it.
grep 'succeeded' input|grep 'failed' A couple of different approaches that only require a single pass through the file:
awk '/succeeded/ && /failed/' file sed -n '/succeeded/ {/failed/ p}' file perl -ne 'print if /succeeded/ and /failed/' file I was hoping grep -e succeeded -e failed file would work, but it returns "one or the other" instead of "both".
To grep for 2 words existing on the same line with AND
grep succeeded FILE | grep failed grep succeeded FILE will print all lines that have succeedded in them from FILE, and then grep failed will print the lines that have failed in them from the result of grep succeeded FILE. Hence, if you combine these using a pipe, it will show lines containing both succeeded and failed.
grep 'failed' <(grep 'succeeded' inputFile) 