I have an array of pages
var $pages = ["events", "template", "privacy", "terms", "mentor", "party", "getinvolved", "tools"]; What I want to do is
if ( $body[0].id !== anyOfThePageInTheArray ) { //do something here }); How can I do like if the page that they are on is not one of the page that is in the array.
I have tried .inArray and .each but I think maybe I'm doing it wrong or something.
The native Array.indexOf works fine:
if ($pages.indexOf($body[0].id) === -1) { // It's not in there } But if you insist on jQuery:
if ($.inArray($body[0].id, $pages) === -1) { // It's not in there } Try:
if($pages.indexOf($body[0].id) == -1){ //code here } You should use
if($.inArray($body[0].id,$pages) === -1) When the second argument isn't in the array (first argument), it will return -1. Otherwise, it returns the index of the element.
By the way, $body[0].id returns e.g. "events", or is a number?
console.log($body[0].id); console.log($pages); to know what's going wrong...===