Getting a "too many values to unpack" value error

Question

I've looked at other answers but it looks like they use 2 different values.

The code:

user = ['X', 'Y', 'Z'] info = [['a','b','c',], ['d','e','f'], ['g','h','i']] for u, g in user, range(len(user)): print '|',u,'|',info[g][0],'|',info[g][1],'|',info[g][2],'| \n'

So basically, it needs to output:

'| X | a | b | c |' '| Y | d | e | f |' '| z | g | h | i |'

But instead, I get this error:

Traceback (most recent call last): File "<pyshell#19>", line 1, in <module> for u, g in user, range(len(user)): ValueError: too many values to unpack

As far as I know both user and range(len(user)) are of equal value.

Aside: If you really do want a list and its indexes, try: for g,u in enumerate(user):. But, as others have said, in this case you don't want indexes, you want zip. — Robᵩ
– Robᵩ, Commented Jul 2, 2013 at 14:04

Ashwini Chaudhary · Accepted Answer · 2013-09-04 17:51:58Z

for u,g in user, range(len(user)):

is actually equivalent to:

for u,g in (user, range(len(user))):

i.e a tuple. It first returns the user list and then range. As the number of items present in user are 3 and on LHS you've just two variable (u,b), so you're going to get that error.

>>> u,g = user Traceback (most recent call last): File "<ipython-input-162-022ea4a14c62>", line 1, in <module> u,g = user ValueError: too many values to unpack

You're looking for zip here(and use string formatting instead of manual concatenation):

>>> user = ['X', 'Y', 'Z'] >>> info = [['a','b','c',], ['d','e','f'], ['g','h','i']] for u, g in zip(user, info): print "| {} | {} |".format(u," | ".join(g)) ... | X | a | b | c | | Y | d | e | f | | Z | g | h | i |

mshameers · Accepted Answer · 2013-07-03 04:52:52Z

for u in user: print '|',u,'|',info[user.index(u)][0],'|',info[user.index(u)][1],'|',info[user.index(u)][2],'| \n'

sufinsha · Accepted Answer · 2013-07-03 04:54:09Z

>>> g = 0 >>> for u in user: ... print '|',u,'|',info[g][0],'|',info[g][1],'|',info[g][2],'| \n' ... g=g+1 ... | X | a | b | c | | Y | d | e | f | | Z | g | h | i |

icyflame · Accepted Answer · 2013-07-03 05:05:22Z

The following code works too:

>>> for i in zip(user,info): print i[0],'|', for x in i[1]: print x,'|', print

And I get the output:

X | a | b | c | Y | d | e | f | Z | g | h | i |

P.S.:I know there have been a couple of answers, But I just thought this is also a way to get the result and thats why I have added it!

Collectives™ on Stack Overflow

Getting a "too many values to unpack" value error

4 Answers 4

Comments

Comments

Comments

Comments

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

Comments

Comments

Related