I've recently written a password script in batch. Basically it takes the password from a different batch script, finds out how many characters it has, takes the password from the user and compares them. However, nothing is ever simple with me and I've gotten into some nested FOR loops and such. It's hard to explain, so here's the code:
@echo off setlocal enabledelayedexpansion call pass.bat & rem Sets the variable "pass" as "default". set map=abcdefghijklmnopqrstuvwxyz set len=0 for /l %%A in (12,-1,0) do ( set /a "len|=1<<%%A" for %%B in (!len!) do if "!pass:~%%B,1!"=="" set /a "len&=~1<<%%A" ) for /l %%C in (1,1,100) do ( set letter%%C=!pass:~%%C,1! ) :pass for /l %%D in (0,1,%len%) do ( cls choice /c "abcdefghijklmnopqrstuvwxyz" /n /m "Password: !ast!" set /a charerr=!errorlevel!-1 for /l %%E in (0,1,25) do ( set password=!password!%map:~!charerr!,1% & rem This is the problem line. ) set ast=!ast!* ) if "%pass%" neq "%password%" goto fail cls echo Correct Password echo pass: %pass% echo password: %password% >nul pause exit :fail set /a tries-=1 if %tries% geq 1 goto pass Now, the script doesn't crash or anything like that, however it does not set password as the password you entered.
If you run it you'll understand.
Note: pass.bat purely contains the line set pass=default
