Starting Keyboard Navigation from SelectedItem in a ListView (WPF)

Question

I am working on a WPF ListView and I want to use the keyboard navigation which actually works fine right now. The problem is as follows:

I listen to SelectionChanged on the ListBox
inside the event handler I bring the selected Item into view (which works fine)
when I start Keyboard navigation it starts from the top of the list, not from the SelectedItem (which is the thing i don't want).

So the question is now: how can I start keyboard navigation (up and down arrows) from the SelectedItem instead of the first Item?

Here ist what my event handler looks like:

protected void ListSelectionChanged ( Object sender , SelectionChangedEventArgs args ) { var enumerator = args.AddedItems.GetEnumerator( ); if ( enumerator.MoveNext( ) ) ( sender as ListView ).ScrollIntoView( enumerator.Current ); }

Thx in advance!

possible duplicate of stackoverflow.com/questions/9689987/… — dnr3
– dnr3, Commented Sep 3, 2013 at 9:26
try set the focus to your selectedItem within the ListSelectionChanged event handler. I think keyboard navigation is about focus not selection. — Bolu
– Bolu, Commented Sep 3, 2013 at 9:31

Sheridan · Accepted Answer · 2013-09-03 09:33:36Z

4

I think that @Bolu has correctly answered your question. The problem relates to the Focus of the item, not the selection. When you change the SelectedItem, try adding this line just afterwards:

item.Focus();

answered Sep 3, 2013 at 9:33

Sheridan

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2 Comments

msfriese Over a year ago

Thank you, calling Focus() was the right thing to do. Anyways I had some problems getting the Item to call Focus on. The first reason was: It was not there yet. The second one was: It was out of sight so the Virtualization did not create it. To solve this I had to ScrollIntoView(value) first and then listen to ItemsContainerGenerator.StatusChanged to have the item created. Finally i could savely call focus and everything worked out fine.

DJH Over a year ago

For future reference, here's another method. The answer to that question is the complete code for this question.

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