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Currently in my app, I have my own URI scheme to detect when user clicks on a particular URI.

Code used in Manifest file is as below:

<intent-filter> <category android:name="android.intent.category.DEFAULT" /> <category android:name="android.intent.category.BROWSABLE" /> <data android:scheme="http" android:host="com.test/> <action android:name="android.intent.action.VIEW" /> </intent-filter>

If a user clicks on a link which has my custom URI in browser, It will now popup a options for user to choose my app.

But how do I pass this data which is the link to my app when started for further processing? Basically how do I pass data from browser to my app?

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  • Why do you set android.intent.action.VIEW twice? Commented Aug 6, 2015 at 18:41
  • @portfoliobuilder Should be once, guess it didn't threw any error if written twice, so would have missed it. Commented Aug 7, 2015 at 1:12

1 Answer 1

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Suppose that your url is: http://twitter.com/status/1234
You can get the data using the following method.

 // http://twitter.com/status/1234 Uri data = getIntent().getData(); Log.d(TAG, data.toString()); String scheme = data.getScheme(); // "http" Log.d(TAG, scheme); String host = data.getHost(); // "twitter.com" Log.d(TAG, host); String inurl = data.toString(); List<String> params = data.getPathSegments(); String first = params.get(0); // "status" String second = params.get(1); // "1234"
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2 Comments

I always get null in Paths:( But data is correct and not null.
data.pathSegments is empty

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