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xml:

<entry> <link rel="http://schemas.google.com/g/2005#feed" type="application/atom+xml" href="http://picasaweb.google.com/data/feed/api/user/xy/albumid/531885671007533108" /> <link rel="alternate" type="text/html" href="http://picasaweb.google.com/xy/Cooking" /> <link rel="self" type="application/atom+xml" href="http://picasaweb.google.com/data/entry/api/user/xy/albumid/531885671007533108" /> </entry>

Here's what I've tried:

foreach($xml->entry as $feed) { $album_url = $feed->xpath("./link[@rel='alternate']/@href"); echo $album_url; }

I've tried all kinds of permutations, too but no luck.

Expected result would be http://picasaweb.google.com/xy/Cooking

The result I get is "". Can someone explain what I'm doing wrong?

Can someone please help me out? I've been at this for hours...

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2 Answers 2

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xpath() returns an array, you have to select the first element of that array, at index 0. Attention: if there's no match, it may return an empty array. Therefore, you should add an if (isset($xpath[0])) clause, just in case.

foreach ($xml->entry as $entry) { $xpath = $entry->xpath('./link[@rel="alternate"]/@href'); if (isset($xpath[0])) { echo $xpath[0], "\n"; } }
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Comments

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You were close:

./link[@rel='alternate']/@href

Should be the correct XPath to get those values.

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2 Comments

Hey Jacob, thanks for the answer... I tried to use your entry as above, but it still is returning no value.
Josh Davis's answer is correct; xpath returns multiple values. You could just be getting back an array.

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