Submitting an actionLink to a form mvc4

Question

We have a list of action links

Partial View

@foreach (var item in Model.Regions) { <tr> <td> @Html.DisplayFor(modelItem => item.RegionName) </td> <td> <input type="submit" value="Select" /> </td> @Html.HiddenFor(modelItem => Model.Id) </tr> } </table>

I assume that this isn't the correct way to do this, but if you could point me in the right direction it would be appreciated. I want to submit this data into an existing form

Region View

@using (Html.BeginForm()){ <fieldset> @Html.Partial("_RegionsPartial"); <legend>Create new region</legend> <ol> <li>@Html.LabelFor(m => m.RegionName)</li> <li>@Html.EditorFor(m => m.RegionName)</li> </ol> <input type="submit" value="Next" /> @Html.HiddenFor(model => model.RegionId) </fieldset> }

So you can either submit a new one or submit an existing one. Im not sure how to get the id of an existing one into my model. Here is the controller:

 public ActionResult Region() { var model = new WizardModel(); var getRegions = _facade.FetchRegion(); model.Regions = getRegions; return View(model); } [HttpPost] public ActionResult Region(WizardModel model) { if (model.RegionName != null) { var newRegion = _facade.CreateRegion(model.RegionName); model.RegionId = newRegion.Id; } else { model.RegionName = _facade.FetchRegion(model.RegionId).RegionName; } TempData["suburbModel"] = model; return RedirectToAction("Suburb"); }

Thanks for taking the time

model.RegionName = _facade.FetchRegion(model.RegionId).RegionName; this line is not working? — WannaCSharp
– WannaCSharp, Commented Oct 17, 2013 at 4:07

foxtrotZulu · Accepted Answer · 2013-10-17 03:38:19Z

So heres my example of passing an instance of a model. I've got a view with many courses so I need to click a button and fire an action, thus carrying all data (including relevant ID) of the course clicked. So in the end I carry the instance I need with the hidden fields.:)

My course model...

public class CourseModel { public int RecordId { get; set; } public string StudentNameField { get; set; } public string SubjectField { get; set; } public string CatalogField { get; set; } public string SectionField { get; set; } public string InstrNameField { get; set; } public string MtgStartField { get; set; } public string MtgEndField { get; set; } }

My main View...Called "CourseList" in Views folder

<div id="container"> <div class="selectLabel">Select a Course:</div><br /> @foreach (var item in Model) { @Html.DisplayFor(model=>item) } </div>

My Display template - Its a view called "CourseModel" in Shared\DisplayTemplates ...For your display template, you could make a unique model for existing & new. Using your "existing" model in the displaytemplate, it results in multiple forms, each using a button type=submit to submit the form with model instance. Use CSS to model the button like a link. If you still need to use actionlink, carry the iD as one of the params.

@using LecExamRes.Helpers @model LecExamRes.Models.SelectionModel.CourseModel @using (Html.BeginForm("CourseList", "Home", null, FormMethod.Post)) { <div class="mlink"> @Html.AntiForgeryToken() @Html.EncryptedHiddenFor(model => model.RecordId) @Html.EncryptedHiddenFor(model => model.CatalogField) @Html.EncryptedHiddenFor(model => model.SectionField) @Html.EncryptedHiddenFor(model => model.SubjectField) @Html.EncryptedHiddenFor(model => model.InstrNameField) @Html.EncryptedHiddenFor(model => model.MtgStartField) @Html.EncryptedHiddenFor(model => model.MtgEndField) <p> <input type="submit" name="gbtn" class="groovybutton" value="@Model.SubjectField - @Model.CatalogField - @Model.SectionField : @Model.InstrNameField"> </p> </div> }

My controller, Courselist [POST] Action...

 [ValidateAntiForgeryToken] [HttpPost] public ActionResult CourseList(SelectionModel.CourseModel model) { //....do something with my model }

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