STL: container of container

Question

I'm noob but as i know it doesnt matter what's data type container contains. So here is what i'm trying to do:

std::deque<list<U32> > ReqLis;

And result of it is next:

error: ISO C++ forbids declaration of 'deque' with no type error: invalid use of '::' expected ';' before '<' token

But when instead of it i try to do this:

std::list<list<U32> > ReqList;

That's ok..................

Question is am i such great noob or is it compiler fail? I'm using gcc/g++

Sorry, i think i'm total noob. I really forgot to include it and dont bother yourself with U32 it's ok — Douman
– Douman, Commented Oct 18, 2013 at 11:06

kokorins · Accepted Answer · 2013-10-21 19:39:06Z

Could you list all the code? The usage of namespaces in your code a bit loose.

The deque in a separate header cpp reference

#include <deque>

Preetam Singh · Accepted Answer · 2013-10-18 07:05:38Z

There is no standard type called U32, but if you #include (stdint.h for C) you can use std::uint32_t1, a 32 bit unsigned integer, which is (I assume) what you want.

first you should include this header file for user u32

 #include <cstdint> std::deque<std::list<std::uint32_t>> ReqList;

Birendra Kumar · Accepted Answer · 2013-10-18 07:24:55Z

Add following :

#include <list> #include<deque> #include<stdint.h> std::deque<uint32_t> ReqList; #include<deque> is for deque data type #include<list> is for list data type #include<stdint.h> is for uint32_t (Integer type with a width of exactly 8, 16, 32, or 64 bits.For signed types, negative values are represented using 2's complement.

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