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I am not quite sure how to print my output into a file.

Sample input

0 2 1 3 5

Content of dragon.dat for sample input 

S SLSLSRS SLS SLSLSRSLSLSRSRS SLSLSRSLSLSRSRSLSLSLSRSRSLSRSRSLSLSLSRSLSLSRSRSRSLSLSRSRSLSRSRS

Here is my code:

infile = open("dragon.dat", "w") def B(n): if n>22: return "Enter integer less than 22" elif n==0: return "S" str=B(n-1) reversestr=str str +="L" reversestr=reversestr.replace("L","T") reversestr=reversestr.replace("R","L").replace("T","R") reversestr=reversestr[::-1] return str + reversestr print(B(0)) # these input will be printed in the python shell print(B(2)) print(B(1)) print(B(3)) print(B(5)) infile.write(B(0)) infile.write(B(2)) infile.write(B(1)) infile.write(B(3)) infile.write(B(5)) infile.close()

my ouput in the file:

SSLSLSRSSLSSLSLSRSLSLSRSRSSLSLSRSLSLSRSRSLSLSLSRSRSLSRSRSLSLSLSRSLSLSRSRSRSLSLSRSRSLSRSRS

How am I able to separate them into each lines just like the sample output?

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  • 2
    Use '\n' : infile.write(B(0) + '\n') Commented Oct 24, 2013 at 5:08

3 Answers 3

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You are missing a \n while writing. Use infile.write(B(i) + '\n') instead.

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infile.write("\n".join([B(i) for i in range(6)])
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Use print: print(B(1), file=infile) or 

print(*[B(i) for i in [0,2,1,3,5]], file=infile, sep='\n')
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