Creating lists of random length in python

import random start = 1 end = random.randint(3, 8) l = range(start, end + 1) 

An itertools approach - which also means if you don't need to materialise the list, then you don't have to:

from itertools import count, islice from random import randint mylist = list(islice(count(1), randint(3, 8))) 

Since count is a generator incrementing by 1 each time, we use islice to "limit" the total number of items we take from it, and then build a list.

you can do it using range() where the first argument is the start and the second argument is the random length

import random range(1, random.randint(3, 8)) 

If you specify 4 at the bottom end and 9 as the top of randint you'll get up to 8 numbers like you ask for. You need to do this because you start the range at 1.

>>> import random >>> range(1, random.randint(4,4)) [1, 2, 3] >>> range(1, random.randint(9,9)) [1, 2, 3, 4, 5, 6, 7, 8] >>> rand_list = range(1, random.randint(4,9)) >>> rand_list [1, 2, 3, 4, 5, 6, 7] 

Range() first argument is the starting point. The 2nd argument is the stop. Many of the other answers will sometimes return only two numbers, in the cases where stop == 3.

>>> range(1,3) [1, 2] >>> range(1,4) [1, 2, 3] >>> range(1,8) [1, 2, 3, 4, 5, 6, 7] >>> range(1,9) [1, 2, 3, 4, 5, 6, 7, 8] 

from random import randint l = range(1,randint(3,8)+1 ) print l