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i want to measure about 1000 digits after zero of a number, but i don't know what to do with it to print all of the numbers because it just prints the first 16 numbers what should i do to have them all printed? i tried to change it to string but the problem is that this big number is made by a bigger number which should be the denominator and another problem is that this number is sum of an iterator and i cannot change it to string in each step i tried to make it a product of 10 for example 10^10 or bigger but it didnt answer and it just printed 17 numbers

this is the code:

S=0 for k in range(n+1): S+=((factorial(6*k))*(13591409+545140134*k))/((factorial(3*k))*((factorial(k))**3)*((-640320)**(3*k))) X=((426880*((10005)**0.5))/S) print(X)
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    whoa. This: . is a period. It separates lexical groupings we call "sentences" from one another. Please utilize it. Commented Nov 17, 2013 at 5:55
  • Python floating point numbers use IEEE 754 representation, which allows for 53 bits, which is 15-17 digits when all is said and done. You likely need a much larger number library to do these calculations. Commented Nov 17, 2013 at 5:55

1 Answer 1

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Use the decimal module:

>>> import decimal >>> decimal.getcontext().prec = 100 #Set precision >>> decimal.Decimal('22') / decimal.Decimal('7') Decimal('3.142857142857142857142857142857142857142857142857142857142857142857142857142857142857142857142857143')
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2 Comments

Or maybe fractions, if all the numbers are rational and exact answers really matter.
i tried fractions but the answers were the same, it didn't answer right

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