Using 'super' when subclassing python class that is not derived from `object`(old-style?)

Question

I'm playing with subclassing OptionParser from the std library module optparser. (Python 2.5.2) When I attempt it I get the exception:

TypeError: super() argument 1 must be type, not classobj

Looking at OptionParser, it is not derived from object. So I added object as a parent class, (shown below) and super works properly.

from optparse import OptionParser, Option class MyOptionParser(OptionParser, object): """Class to change """ def __init__(self, usage=None, option_list=None, option_class=Option, version=None, conflict_handler="error", description=None, formatter=None, add_help_option=True, prog=None, epilog=None, ): super(MyOptionParser, self).__init__(usage, option_list, option_class, version, conflict_handler, description, formatter, add_help_option, prog, epilog) if __name__ == '__main__': """Run a quick test """ parser = MyOptionParser() parser.add_option("-t", "--test", type="string", dest="test") (options, args) = parser.parse_args() print "The test option is: %s" % options.test

Is this the correct way to go about it?

kibitzer · Accepted Answer · 2010-01-08 00:16:34Z

Yes I dont see why it would not work. You just need to add couple of spaces right before that super call - as it's written right now, it is not part of your custom init method. Also, a shortcut you might want to use is **kwargs - you can do kwargs key check in your method if thats what you desire to do:

class MyOptionParser(OptionParser, object): """Class to change """ def __init__(self, **kwargs): # You can limit kwargs keys here super(MyOptionParser, self).__init__(**kwargs)

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