Copy Constructor and memory allocation

Question

Why is the memory address of message.pmessage the same before and after the constructor is called? Shouldn't the memory address of message.pmessage be different if it was allocated with new? I'm confused.

Overloaded Operator function

CMessage operator+(const CMessage& aMess) const { cout << "Add operator function called." << endl; size_t len = strlen(pmessage) + strlen(aMess.pmessage) + 1; CMessage message; // cout << &message.pmessage << endl; cout << message.pmessage << endl; message.pmessage = new char[len]; message.test = new char[len]; cout << &message.pmessage << endl; // strcpy_s(message.pmessage, len, pmessage); strcat_s(message.pmessage, len, aMess.pmessage); return message; }

Constructor

CMessage(const char* text = "Default message") { cout << "Constructor called." << endl; pmessage = new char[strlen(text) + 1]; // Allocate space for text strcpy_s(pmessage, strlen(text)+1, text); // Copy text to new memory }

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@VladfromMoscow When I declare the object message inside the overloaded operator function. — Quaxton Hale
– Quaxton Hale, Commented Nov 28, 2013 at 1:33

yngccc · Accepted Answer · 2013-11-28 01:40:39Z

you are printing the address of a pointer inside one object, of course it is always going to be the same. To print out of the address that pointer is pointing to, you can try this

cout << static_cast<void*>(message.pmessage) << endl;

you need static_cast<void*> because you want to avoid printing the c string.

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