find specific file type from folder and its sub folder

Question

I am writing a method to get specific file type such as pdf or txt from folders and subfolders but I am lacking to solve this problem. here is my code

 // .............list file File directory = new File(directoryName); // get all the files from a directory File[] fList = directory.listFiles(); for (File file : fList) { if (file.isFile()) { System.out.println(file.getAbsolutePath()); } else if (file.isDirectory()) { listf(file.getAbsolutePath()); } }

My current method list all files but I need specific files

Google for FileFilter or see stackoverflow.com/questions/5603966/… — vickirk
– vickirk, Commented Dec 5, 2013 at 13:47

Tim B · Accepted Answer · 2013-12-05 14:25:00Z

For a filtered list without needing recursion through sub directories you can just do:

directory.listFiles(new FilenameFilter() { boolean accept(File dir, String name) { return name.endsWith(".pdf"); }});

For efficiency you could create the FilenameFilter ahead of time rather than for each call.

In this case because you want to scan sub folders too there is no point filtering the files as you still need to check for sub folders. In fact you were very nearly there:

File directory = new File(directoryName); // get all the files from a directory File[] fList = directory.listFiles(); for (File file : fList) { if (file.isFile()) { if (file.getName().endsWith(".pdf")) { System.out.println(file.getAbsolutePath()); } } else if (file.isDirectory()) { listf(file.getAbsolutePath()); } }

i tried your logic but it works only with root directory not with sub folders ...
Ahh, sorry. I missed the requirement for recursion. Yes you are right, this will not list sub folders (unless they happen to end with .pdf). In this case since you need to scan all the files anyway going with the other suggestions of just checking the filename is probably your simplest suggestion. - I'll edit my answer.
What is "listf(file.getAbsolutePath())"? I cannot seem to resolve listf
@Lismore create a method called listf - put this as the contents of the method.

Community · Accepted Answer · 2014-03-22 20:29:09Z

6

if(file.getName().endsWith(".pdf")) { //it is a .pdf file! }

/***/

edited Mar 22, 2014 at 20:29

CommunityBot

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answered Dec 5, 2013 at 13:47

Memran

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Comments

asafm · Accepted Answer · 2013-12-05 13:51:56Z

Try using the FilenameFilter interface in you function http://docs.oracle.com/javase/6/docs/api/java/io/FilenameFilter.html

http://www.mkyong.com/java/how-to-find-files-with-certain-extension-only/ - for a code that has extention filter

Seelenvirtuose · Accepted Answer · 2013-12-05 13:51:09Z

Use File.listFiles(FileFilter).

Example:

File[] fList = directory.listFiles(new FileFilter() { @Override public boolean accept(File file) { return file.getName().endSwith(".pdf"); } });

Karthik Prasad · Accepted Answer · 2013-12-05 13:56:03Z

You can use apache fileUtils class

String[] exte= {"xml","properties"}; Collection<File> files = FileUtils.listFiles(new File("d:\\workspace"), exte, true); for(File file: files){ System.out.println(file.getAbsolutePath()); }

luca · Accepted Answer · 2017-04-20 12:08:09Z

My advice is to use FileUtils or NIO.2.
NIO.2 allows Stream with Depth-First search, for example you can print all files with a specified extension in one line of code:

Path path = Path.get("/folder"); try{ Files.walk(path).filter(n -> n.toString().endsWith(".extension")).forEach(System.out::println) }catch(IOException e){ //Manage exception }

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