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I frequently read code like this:

System.Diagnostics.DebuggableAttribute.DebuggingModes.DisableOptimizations | System.Diagnostics.DebuggableAttribute.DebuggingModes.EnableEditAndContinue | System.Diagnostics.DebuggableAttribute.DebuggingModes.IgnoreSymbolStoreSequencePoints | System.Diagnostics.DebuggableAttribute.DebuggingModes.Default)

in C# program,sometimes parameter like this,what's this meanning ?

I have searched from google,but has no valuable answer,the '|' can not property parsing in Google engine,maybe i use the wrong way when searching.

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  • when | is used as || it is OR operator and here it used as Enum values Commented Dec 8, 2013 at 13:36
  • see msdn Commented Dec 8, 2013 at 13:37

5 Answers 5

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'|' is the bitwise or operator, in this case it is used to create an enum value with all the given bits set.

DebuggingModes is a bitflag enumeration - this means each bit can indicate a flag and a single DebuggingModes value can be used to signal multiple flags.

Enums can be made bitflags using the BitFlagsAttribute:

[FlagsAttribute] public enum DebuggingModes { Default = 0, DisableOptimizations = 1, EnableEditAndContinue = 2, ... }
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It depends. If you're comparing Booleans, it's a non-short-circuiting OR comparison (|| is short-circuiting). For integral types (which includes enums), it's indeed the bitwise OR.
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In this case it seems that it is a Flags enum

[Flags] public enum Types { None = 0, Type1 = 1, Type2 = 2, Type3 = 4, }

So

Types someType = Types.Type1 | Types.Type2;

Would mean that it has both types.

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It is a bitwise OR operator iin C#. Here it is used to create an enum value with all the given set of bits.

Binary | operators are predefined for the integral types and bool. For integral types, | computes the bitwise OR of its operands. For bool operands, | computes the logical OR of its operands; that is, the result is false if and only if both its operands are false.

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It is a logical or operator. see here for a complete explanation.

Main explanation in the doc:

Binary | operators are predefined for the integral types and bool. For integral types, | computes the bitwise OR of its operands. For bool operands, | computes the logical OR of its operands; that is, the result is false if and only if both its operands are false.

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when | is used as || it is OR operator and here it used as Enum values

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