Catch custom exception C++

Question

I have an exception class:

#ifndef OBJECTEXCEPTION_H_ #define OBJECTEXCEPTION_H_ class ObjectException: public std::logic_error { public: ObjectException (const std::string& raison) :std::logic_error(raison){}; }; class Object1Exception: public ObjectException { public: Object1Exception (const std::string& raison) : ObjectException(raison){}; }; #endif

I have a method which throw this exception:

void Object1::myMethod(int type) { if (type == 0) { throw new Object1Exception(type); } ... }

Now I use this method:

try{ obj1->myMethod(0); } catch(Object1Exception& error){ }

But I have this error

terminate called after throwing an instance of 'tp::Object1Exception*'

I don't understand why the exception is not caught.

Never say new in C++ unless you're an expert.

Kerrek SB
– Kerrek SB

2013-12-08 17:31:19 +00:00
Commented Dec 8, 2013 at 17:31 — Kerrek SB
– Kerrek SB, Commented Dec 8, 2013 at 17:31

Community · Accepted Answer · 2017-05-23 11:57:32Z

Code throw Object1Exception(type); without the new; you are throwing a pointer to an exception, not an exception itself.

^{BTW, as commented by polkadotcadaver, the error message was pretty clear, it told you about throwing an instance of some pointer type throwing an instance of 'tp::Object1Exception*'....}

I just want to point out also that the error message told you exactly this - "tp::Object1Exception*", the * meaning pointer.

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