redirect after ajax call and skip .always

Question

I have a standard ajax call from jquery as below.

I would like to check if the json array returned is requesting a new page, and if yes, go there and do not execute the .always callback.

Is there a simple way to do this?

var jqxhr = $.ajax({ url: server_URL + '/index.php', type: 'post', dataType: "json", data: obj }).done(function (data) { if (data['go_location']) { window.location.href = data['go_location']; } else { //other stuff } }).fail(function () { alert("ajax error"); }).always(function () { //other code });

Are you saying that the page redirects your, i.e. 30X HTTP code? or that the JSON has a go_location variable? — Noam Rathaus
– Noam Rathaus, Commented Dec 17, 2013 at 8:29
JSON has a go_location variable such as browse.html i.e. array['go_location']='browse.html' — Ray S.
– Ray S., Commented Dec 17, 2013 at 8:30

Airan · Accepted Answer · 2013-12-17 09:31:45Z

As name says 'always', .always() is executed in both the case either success or failure. You don't wanna execute .always() on success state but failure state, which is not possible. You are calling three methods namely .done(), .fail(), and .always() on ajax response. All the method are triggered as soon as ajax is complete [.done() and .alway() on success otherwise .fail() and .always()]. We know that jquery/js is asynchronous so, even return statement in any of other method can not stop execution of .always(). In your case only option is don't use .always() method. Either of the state success or failure, either .done() or .fail() is executed. So, you can move your .always() method statements to these methods if needed.

 $.ajax({ url: server_URL + '/index.php', type: 'post', dataType: "json", data: obj }).done(function (data) { //Do something if ajax succeeds if (data['go_location']) { window.location.href = data['go_location']; } else { //other stuff } }).fail(function () { //Do something if ajax fails })

are you saying .done will always run before .always (assuming success of ajax request)?
Both are triggered in the order they are chained. As I mentioned Jquery is Asynchronous and .always() will not wait for .done()'s termination.

Arnelle Balane · Accepted Answer · 2013-12-17 08:38:25Z

0

I don't really understand why you have an .always function but I think you could try this:

$.ajax({ url: server_URL + '/index.php', type: 'post', dataType: "json", data: obj, success: function(data) { if (data['go_location']) { window.location.href = data['go_location']; } else { //other stuff } }, error: function(data) { alert("ajax error"); } }

answered Dec 17, 2013 at 8:38

Arnelle Balane

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3 Comments

Ray S. Over a year ago

is success the same as .done? very unclear from the documentation what the difference is between all these handlers .done .always

Arnelle Balane Over a year ago

I'm not really familiar with .done and .always but .success gets executed when the server sends a response back to the AJAX call.

Ray S. Over a year ago

i think .success is deprecated

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