Converting Type Int to Type Byte

Question

I have a small set of code that attempts to bit-shift a 1-bit from the 0 index to the 7 index in a byte. After each bit shift I want to take the int value and convert it to a byte:

for(int t=0; t<8; t++) { int ShiftBit = 0x80 >> t; byte ShiftBitByte = Convert.ToByte(ShiftBit.ToString(),8); }

I would expect the outputs to be:

0x80
0x40
0x20
0x10
0x08
0x04
0x02
0x01

When I run my code I encounter an exception "Additional non-parsable characters are at the end of the string." Is there a better way to capture these bytes?

Thank you

Why don't you just cast to byte or am I missing something?

PaulK
– PaulK

2014-01-28 22:37:19 +00:00
Commented Jan 28, 2014 at 22:37 — PaulK
– PaulK, Commented Jan 28, 2014 at 22:37

Nicholas Carey · Accepted Answer · 2014-01-29 16:32:18Z

Why don't do you this?

for ( int i = 0 ; i < 8 ; ++i ) { int s = 0x80 >> i ; byte b = (byte) s ; )

Or (cleaner):

for ( int i = 0x00000080 ; i != 0 ; i >>1 ) { byte b = (byte) i ; }

To turn a byte into a hex string, something like

byte b = ... string s = string.Format("0x{0:X2}",b) ;

Ought to do you. But a byte is a number, it doesn't have a format (representation) until you turn it into a string a give it one.

Thanks for your feedback. I guess what I am really trying to do is shift a 1 as follows: 10000000 (or 0x80), 01000000 (or 0x40) .... 0x00000001 (or 0x01). Once each bit is shifted I want to capture it in hex format "0x--".

Selman Genç · Accepted Answer · 2014-01-28 22:49:29Z

Are you looking for this ?

for (int t = 0; t < 8; t++) { int ShiftBit = 0x80 >> t; byte ShiftBitByte = (byte) ShiftBit; Console.WriteLine("0x{0:X}",ShiftBitByte); }

enter image description here

See Standard Numeric Format Strings

phoog · Accepted Answer · 2014-01-29 21:24:33Z

You're getting the error because you are erroneously specifying that the string is in base 8. The digit '8' is not a legal digit in base 8, which uses only 0 through 7.

Why not

for (byte b = 0x80; b != 0; b >>= 1)

?

Thanks for catching that ... what I really meant to write was shift a bit in int 0x10000000 from index 0 to 7 and then convert it to a byte each time for an array [0x80, 0x40, 0x20, 0x10, 0x08, 0x04, 0x02, 0x01]. Is that possible?

I don't understand what int 0x10000000 has to do with it. If you want that array, you can achieve that in any of a number of ways:

byte[] xs = { 0x80, 0x40, 0x20, 0x10, 0x08, 0x04, 0x02, 0x01 }; byte[] ys = Enumerable.Range(0, 8).Select(i => (byte)(0x80 >> i)).ToArray(); byte[] zs = new byte[8]; for (int index = 0; index < zs.Length; index++) zs[index] = (byte)(0x80 >> index);

Thanks for catching that ... what I really meant to write was shift a bit in int 0x10000000 from index 0 to 7 and then convert it to a byte each time for an array [0x80, 0x40, 0x20, 0x10, 0x08, 0x04, 0x02, 0x01]. Is that possible?

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